The number of isomers of `C_(6)H_(14)` is:

Options

A. 4
B. 5
C. 6
D. 7

Explanation

To find the number of isomers for the compound \( C_6H_{14} \), we can follow these steps:

### Step 1: Identify the Parent Chain
The molecular formula \( C_6H_{14} \) corresponds to a saturated hydrocarbon, which means it is an alkane. The longest continuous chain of carbon atoms in this case is 6, which corresponds to hexane.

### Step 2: Draw the Straight-Chain Isomer
The first isomer is the straight-chain form, which is hexane itself:
- Structure:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_3 \]

### Step 3: Identify Possible Branching
Next, we can create branched isomers by substituting hydrogen atoms with methyl groups (CH₃) at various positions.

### Step 4: Draw the Branched Isomers
1. **2-Methylpentane**:
- Structure:
\[ \text{CH}_3-\text{CH}-\text{CH}_2-\text{CH}_2-\text{CH}_3 \]
(Methyl group on the second carbon)

2. **3-Methylpentane**:
- Structure:
\[ \text{CH}_3-\text{CH}_2-\text{CH}-\text{CH}_2-\text{CH}_3 \]
(Methyl group on the third carbon)

3. **2,2-Dimethylbutane**:
- Structure:
\[ \text{CH}_3-\text{C}(\text{CH}_3)_2-\text{CH}_2-\text{CH}_3 \]
(Two methyl groups on the second carbon)

4. **2,3-Dimethylbutane**:
- Structure:
\[ \text{CH}_3-\text{CH}-\text{C}(\text{CH}_3)-\text{CH}_3 \]
(One methyl group on the second carbon and one on the third carbon)

### Step 5: Count the Isomers
Now we can count the isomers we have drawn:
1. Hexane
2. 2-Methylpentane
3. 3-Methylpentane
4. 2,2-Dimethylbutane
5. 2,3-Dimethylbutane

### Conclusion
The total number of isomers for \( C_6H_{14} \) is **5**.

### Final Answer
The number of isomers of \( C_6H_{14} \) is **5**.

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