The non-metallic cation is persent in .

Options

A. `CrO_(2)CI_(2)`
B. `VOCI`
C. `OF_(2)`
D. `PF_(3)`

Explanation

To determine which compounds contain a non-metallic cation, we need to analyze the oxidation states of the non-metal elements in each compound provided. Let's go through the compounds step by step.

### Step 1: Analyze Compound A - CrO2Cl2
- **Elements**: Chromium (Cr), Oxygen (O), Chlorine (Cl)
- **Oxidation States**:
- Oxygen typically has an oxidation state of -2.
- Chlorine typically has an oxidation state of -1.
- **Calculation**:
- Let the oxidation state of Cr be x.
- The equation based on the oxidation states is:
\[ x + 2(-2) + 2(-1) = 0 \implies x - 4 - 2 = 0 \implies x = +6 \]
- **Conclusion**: Cr is a metal and has an oxidation state of +6. O and Cl are anions.

### Step 2: Analyze Compound B - BOCl
- **Elements**: Boron (B), Oxygen (O), Chlorine (Cl)
- **Oxidation States**:
- Oxygen is -2.
- Chlorine is -1.
- **Calculation**:
- Let the oxidation state of B be y.
- The equation is:
\[ y + (-2) + (-1) = 0 \implies y - 3 = 0 \implies y = +3 \]
- **Conclusion**: B is a metal and has an oxidation state of +3. O and Cl are anions.

### Step 3: Analyze Compound C - OF2
- **Elements**: Oxygen (O), Fluorine (F)
- **Oxidation States**:
- Fluorine is -1 (more electronegative).
- Therefore, let the oxidation state of O be z.
- **Calculation**:
- The equation is:
\[ z + 2(-1) = 0 \implies z - 2 = 0 \implies z = +2 \]
- **Conclusion**: O has an oxidation state of +2, making it a cation. F is an anion.

### Step 4: Analyze Compound D - PF3
- **Elements**: Phosphorus (P), Fluorine (F)
- **Oxidation States**:
- Fluorine is -1.
- Let the oxidation state of P be w.
- **Calculation**:
- The equation is:
\[ w + 3(-1) = 0 \implies w - 3 = 0 \implies w = +3 \]
- **Conclusion**: P has an oxidation state of +3, making it a cation. F is an anion.

### Final Conclusion
- The compounds that contain non-metallic cations are **OF2** (Oxygen) and **PF3** (Phosphorus).

### Answer
The non-metallic cation is present in **C (OF2)** and **D (PF3)**.