Two types `FXF` angles are presnet in which of the following molecule `(X=S,Xe,C)` ? .

Options

A. `SF_(4)`
B. `XeF_(4)`
C. `SF_(6)`
D. `CF_(4)`

Explanation

To determine which molecule has two types of `FXF` angles, we will analyze the molecular structures of SF4, XeF4, and CF4.

### Step 1: Analyze SF4 (Sulfur Tetrafluoride)
1. **Calculate Valence Electrons**:
- Sulfur (S) has 6 valence electrons.
- Each Fluorine (F) has 7 valence electrons, and there are 4 Fluorine atoms.
- Total = 6 + 4 × 7 = 6 + 28 = 34 valence electrons.

2. **Determine Bond Pairs and Lone Pairs**:
- Divide the total by 8: 34 / 8 = 4 (quotient) and 2 (remainder).
- Bond pairs = 4, Lone pairs = 1 (since remainder is 2, which means 1 lone pair).

3. **Hybridization**:
- The hybridization is sp³d (4 bond pairs and 1 lone pair).

4. **Molecular Geometry**:
- The shape is seesaw.
- Bond angles are approximately 120°, 90°, and 180°.

### Step 2: Analyze XeF4 (Xenon Tetrafluoride)
1. **Calculate Valence Electrons**:
- Xenon (Xe) has 8 valence electrons.
- Each Fluorine (F) has 7 valence electrons, and there are 4 Fluorine atoms.
- Total = 8 + 4 × 7 = 8 + 28 = 36 valence electrons.

2. **Determine Bond Pairs and Lone Pairs**:
- Divide the total by 8: 36 / 8 = 4 (quotient) and 4 (remainder).
- Bond pairs = 4, Lone pairs = 2 (since remainder is 4, which means 2 lone pairs).

3. **Hybridization**:
- The hybridization is sp³d² (4 bond pairs and 2 lone pairs).

4. **Molecular Geometry**:
- The shape is square planar.
- Bond angles are 90° and 180°.

### Step 3: Analyze CF4 (Carbon Tetrafluoride)
1. **Calculate Valence Electrons**:
- Carbon (C) has 4 valence electrons.
- Each Fluorine (F) has 7 valence electrons, and there are 4 Fluorine atoms.
- Total = 4 + 4 × 7 = 4 + 28 = 32 valence electrons.

2. **Determine Bond Pairs and Lone Pairs**:
- Divide the total by 8: 32 / 8 = 4 (quotient) and 0 (remainder).
- Bond pairs = 4, Lone pairs = 0.

3. **Hybridization**:
- The hybridization is sp³ (4 bond pairs and 0 lone pairs).

4. **Molecular Geometry**:
- The shape is tetrahedral.
- Bond angles are approximately 109.5°.

### Conclusion:
- SF4 has bond angles of 120°, 90°, and 180°.
- XeF4 has bond angles of 90° and 180°.
- CF4 has bond angles of 109.5°.
- **The correct answer is XeF4 (B)**, as it has two types of `FXF` angles (90° and 180°).