In a regular octahedral molecule `SF_(6)` the number of `F-S-F` bonds at `180^(@)` is .

Options

A. `2`
B. `3`
C. `4`
D. `6`

Explanation

To solve the question regarding the number of `F-S-F` bonds at `180°` in the regular octahedral molecule `SF6`, we can follow these steps:

### Step 1: Understand the Structure of SF6
- The molecule `SF6` has a regular octahedral geometry. This means that the sulfur (S) atom is at the center, and the six fluorine (F) atoms are positioned at the vertices of an octahedron.

### Step 2: Visualize the Bond Arrangement
- In an octahedral structure, there are four fluorine atoms in the equatorial plane and one fluorine atom above and one below the plane. This gives us a 3D arrangement where some bonds can be at `180°` to each other.

### Step 3: Identify the Bonds at 180°
- To find the `F-S-F` bonds that are at `180°`, we need to look for pairs of fluorine atoms that are directly opposite each other across the sulfur atom.
- In the octahedral structure, there are three pairs of opposite fluorine atoms:
1. F1 and F4
2. F2 and F5
3. F3 and F6

### Step 4: Count the Number of 180° Bonds
- Each of these pairs represents a bond angle of `180°`. Therefore, we can count:
- F1-S-F4 (180°)
- F2-S-F5 (180°)
- F3-S-F6 (180°)

### Conclusion
- Thus, the total number of `F-S-F` bonds at `180°` in the `SF6` molecule is **3**.

### Final Answer
- The number of `F-S-F` bonds at `180°` in `SF6` is **3**.