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The maximum number of 90^(@) angles betw...

The maximum number of `90^(@)` angles between bp-bp of electrons is observed in .

A

`sp^(3)` d hybridisation

B

`dsp^(3)` hybridisation

C

`dsp^(2)` hybridisation

D

`sp^(3) d^(2)` hybridisation

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To determine the maximum number of 90-degree angles between bond pairs (bp-bp) of electrons, we will analyze the hybridization and molecular geometry of the given options. ### Step 1: Identify the Hybridization The question mentions the hybridization states, so we need to identify them. The common hybridizations to consider are: - sp - sp² - sp³ - sp³d - sp³d² ### Step 2: Analyze sp³d Hybridization For sp³d hybridization, the molecular geometry is typically trigonal bipyramidal. In this geometry: - There are five bond pairs (AX₅). - The arrangement consists of three equatorial positions in one plane and two axial positions above and below this plane. ### Step 3: Count the 90-Degree Angles In the trigonal bipyramidal structure: - The equatorial bonds are 120 degrees apart from each other. - The axial bonds are perpendicular (90 degrees) to the equatorial plane. The 90-degree angles can be counted as follows: - Each axial bond forms a 90-degree angle with the three equatorial bonds. - Therefore, for each of the two axial bonds, there are three 90-degree angles. Thus, the total number of 90-degree angles is: - 2 axial bonds × 3 equatorial bonds = 6 angles. ### Conclusion The maximum number of 90-degree angles between bond pairs (bp-bp) of electrons is observed in sp³d hybridization, resulting in a total of 6 angles.

To determine the maximum number of 90-degree angles between bond pairs (bp-bp) of electrons, we will analyze the hybridization and molecular geometry of the given options. ### Step 1: Identify the Hybridization The question mentions the hybridization states, so we need to identify them. The common hybridizations to consider are: - sp - sp² - sp³ - sp³d ...
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The shape of a moleculs is determined by electron pair repulsions in the valence shell A.lp occupies a larger space than a bp because it is not shared by two nuclei The the lp lp repulsion is greater than the lp-bp repulsion, which in trun is greater the bp-bp repulsion. The presence of lp causes distortion of bond angles hence, a daviation from an ideal shape THe extent of distortion depends upon the orientation of the lp's around the central atom In a trigonal bipyramid, the lp's occupy equatorial positions than the apical ones In AB_(n) type molecules, as the EN of A increases, the bp's come closer and the repulsion between them increases. On the other hand, as EN of B increases, the lp s get farther and repulsion decreases In which of the following molecules is the bond angle largest ? .

The shape of a moleculs is determined by electron pair repulsions in the valence shell A.lp occupies a larger space than a bp because it is not shared by two nuclei The the lp lp repulsion is greater than the lp-bp repulsion, which in trun is greater the bp-bp repulsion. The presence of lp causes distortion of bond angles hence, a daviation from an ideal shape THe extent of distortion depends upon the orientation of the lp's around the central atom In a trigonal bipyramid, the lp's occupy equatorial positions than the apical ones In AB_(n) type molecules, as the EN of A increases, the bp's come closer and the repulsion between them increases. On the other hand, as EN of B increases, the lp s get farther and repulsion decreases The shape of which of the following molecules will not be distored ?

CENGAGE CHEMISTRY ENGLISH-CHEMICAL BONDING AND MOLECULAR STRUCTURE-Exercises Single Correct (Hybridisation)
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