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Out of CH(3)^(o+),H(3)O^(o+),NH(3),CH(3)...

Out of `CH_(3)^(o+),H_(3)O^(o+),NH_(3),CH_(3)^(Theta)` the species which is not isoelectronic is________.

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To determine which of the given species is not isoelectronic, we need to calculate the total number of electrons in each species. Isoelectronic species are those that have the same number of electrons. Let's analyze each species step by step. ### Step 1: Calculate the number of electrons in CH₃⁺ - Carbon (C) has 6 electrons. - Each hydrogen (H) has 1 electron, and there are 3 hydrogen atoms, contributing 3 electrons. - Since CH₃⁺ has a positive charge, it means it has lost 1 electron. **Calculation:** \[ \text{Total electrons in CH}_3^+ = 6 \, (\text{C}) + 3 \, (\text{H}) - 1 \, (\text{charge}) = 8 \, \text{electrons} \] ### Step 2: Calculate the number of electrons in H₃O⁺ - Oxygen (O) has 8 electrons. - There are 3 hydrogen atoms, contributing 3 electrons. - H₃O⁺ has a positive charge, so it has lost 1 electron. **Calculation:** \[ \text{Total electrons in H}_3\text{O}^+ = 8 \, (\text{O}) + 3 \, (\text{H}) - 1 \, (\text{charge}) = 10 \, \text{electrons} \] ### Step 3: Calculate the number of electrons in NH₃ - Nitrogen (N) has 7 electrons. - There are 3 hydrogen atoms, contributing 3 electrons. - NH₃ is neutral, so there is no charge to consider. **Calculation:** \[ \text{Total electrons in NH}_3 = 7 \, (\text{N}) + 3 \, (\text{H}) = 10 \, \text{electrons} \] ### Step 4: Calculate the number of electrons in CH₃⁻ - Carbon (C) has 6 electrons. - There are 3 hydrogen atoms, contributing 3 electrons. - CH₃⁻ has a negative charge, meaning it has gained 1 electron. **Calculation:** \[ \text{Total electrons in CH}_3^- = 6 \, (\text{C}) + 3 \, (\text{H}) + 1 \, (\text{charge}) = 10 \, \text{electrons} \] ### Conclusion Now we summarize the total number of electrons for each species: - CH₃⁺: 8 electrons - H₃O⁺: 10 electrons - NH₃: 10 electrons - CH₃⁻: 10 electrons The species that is not isoelectronic is **CH₃⁺**, as it has 8 electrons, while the others have 10 electrons. ### Final Answer The species which is not isoelectronic is **CH₃⁺**.

To determine which of the given species is not isoelectronic, we need to calculate the total number of electrons in each species. Isoelectronic species are those that have the same number of electrons. Let's analyze each species step by step. ### Step 1: Calculate the number of electrons in CH₃⁺ - Carbon (C) has 6 electrons. - Each hydrogen (H) has 1 electron, and there are 3 hydrogen atoms, contributing 3 electrons. - Since CH₃⁺ has a positive charge, it means it has lost 1 electron. **Calculation:** ...
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CENGAGE CHEMISTRY ENGLISH-CHEMICAL BONDING AND MOLECULAR STRUCTURE-Exercises Fill In The Blanks
  1. The type of hybrid orbitals used by chlorine atom in ClO(2)^(-) is

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  2. The cyanide ion CN and N(2) are isoelectronic, but in contrast to CN^(...

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  3. The shape of [CH(3)]^(o+) is .

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  4. The valence atomic orbital on C in silver acetylide is ……………hybridised...

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  5. Out of CH(3)^(o+),H(3)O^(o+),NH(3),CH(3)^(Theta) the species which is ...

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  6. The experimentally determined N-F bond length in NF(3) is than the sum...

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  7. When N(2) goes to N(2)^(+), the N-N bond distance …………

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  8. The central bond in 1,3 butadiene is than that of n-butane .

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  9. Out of (A) toluene (B) m-dichloro benzene (C ) o-dichloro benzene and ...

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  10. In BaC(2)sigma andpi bonds are present between two C-atoms .

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  11. During the formation of a chemical bond potential energy of the system

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  12. Comparatively low melting point and insolubility in water of AlCl(3) i...

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  13. The dipole moment of CH(3)OH isthan that of CH(3)SH .

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  14. What is the correct dipole moment of NH(3) and NF(3) respectively ?

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  15. In a compound A,B if the element B attracts electrons more than elemen...

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  16. The strenght of covalent bond will depend on the extent to which atomi...

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  17. Salicyaldehyde involveshydrogen bonding .

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  18. The bond multiplicity leads to ............ in bond distance.

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  19. The angle between two covalent bonds is maximum for (CH(4), H(2)O, CO(...

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  20. Due to hybridisationhybrid orbitals are formed .

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