In `BaC_(2)`_______sigma and________pi bonds are present between two C-atoms .

Explanation

To determine the number of sigma and pi bonds present between the two carbon atoms in barium carbide (BaC₂), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**:
- We are dealing with barium carbide, which has the formula BaC₂. This indicates that there are two carbon atoms in the compound.

2. **Understand the Ionic Nature**:
- Barium (Ba) is a metal that forms a +2 ion (Ba²⁺). The carbide ion (C₂²⁻) consists of two carbon atoms that are bonded together.

3. **Draw the Structure of the Carbide Ion (C₂²⁻)**:
- The two carbon atoms in the carbide ion are bonded together with a triple bond. A triple bond consists of one sigma bond and two pi bonds.

4. **Count the Bonds**:
- In a triple bond:
- There is **1 sigma bond** (σ bond).
- There are **2 pi bonds** (π bonds).

5. **Conclusion**:
- Therefore, between the two carbon atoms in BaC₂, there is **1 sigma bond** and **2 pi bonds**.

### Final Answer:
In BaC₂, there is **1 sigma bond** and **2 pi bonds** present between the two carbon atoms.

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