The dipole moment of `CH_(3)OH` is_____than that of `CH_(3)SH` .

Explanation

To determine the dipole moment of CH₃OH (methanol) in comparison to CH₃SH (methanethiol), we can follow these steps:

### Step 1: Understand the concept of dipole moment
The dipole moment is a measure of the separation of positive and negative charges in a molecule. It depends on the polarity of the bonds and the molecular geometry.

### Step 2: Identify the electronegativity of the atoms involved
- Oxygen (O) has a higher electronegativity (approximately 3.5 on the Pauling scale) compared to sulfur (S), which has an electronegativity of about 2.5.
- This means that the O-H bond in CH₃OH is more polar than the S-H bond in CH₃SH.

### Step 3: Analyze the bond polarity
- In CH₃OH, the O atom pulls electron density towards itself more strongly than the S atom in CH₃SH.
- The C-O bond in CH₃OH is more polar than the C-S bond in CH₃SH due to the greater electronegativity difference between carbon and oxygen compared to carbon and sulfur.

### Step 4: Compare the overall molecular polarity
- Since CH₃OH has more polar bonds (C-O and O-H) compared to CH₃SH (C-S and S-H), the overall dipole moment of CH₃OH will be greater.
- The geometry of both molecules is similar (both are tetrahedral around the carbon), so the bond polarities will directly influence the dipole moments.

### Conclusion
The dipole moment of CH₃OH is greater than that of CH₃SH.

### Final Answer
The dipole moment of CH₃OH is **greater** than that of CH₃SH.

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