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Hardness of water is 200 ppm. The normal...

Hardness of water is 200 ppm. The normality and molarity of `CaCO_3` in the water is
(a). `2xx10^(-6)(N,2xx10^(-6)M`
(b). `4xx10^(-2)N,2xx10^(-2)M`
(c). `4xx10^(-3)N,2xx10^(-3)M`
(d). `4xx10^(-1)N,2xx10^(-1)M`

A

`2xx10^(-6) N, 2xx10^(-6) M`

B

`4xx10^(-2) N, 2xx10^(-2) M`

C

`4xx10^(-3) N, 2xx10^(-3) M`

D

`4xx10^(-1) N, 2xx10^(-1) M`

Text Solution

Verified by Experts

The correct Answer is:
C
Hardness is weight in grams of `CaCO_(3)` in `10^(6) mL` of `H_(2)O`
or `=10^(6)gof H_(2)O` `( :'dH_(2)O=1)`
`MW(CaCO_(3))=100gmol^(-1)`
`M=(W_(2)xx1000)/(MWxx"Volume of solution in mL")`
`=(200xx1000)/(100xx10^(6))=2xx10^(-3)M`
`N=nxxM=2xx2xx10^(-3)=4xx10^(-3)N`
Hence, the correct option is (c).
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