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Calculate the number of moles and weight of `O_2` produced on heating 1.12 L of 10 volume strength of `H_2O_2` at STP.

Text Solution

Verified by Experts

Volume of `O_(2)` at `STP`
=volume of `H_(2)O_(2)xx` volume strength of `H_(2)O_(2)`
`=1.12 Lxx10=11.2 L`
Moles of `O_(2)` at `STP=(11.2 L)/(22.4 L)=0.5 mol`
Weight of `O_(2)=0.5xx32=16.0 g`
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