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Hydrogen peroxide is a powerful oxidisin...

Hydrogen peroxide is a powerful oxidising agent, both in the acidic and alkaline medium.
In acidic medium: `H_(2)O_(2)+2H^(o+)+2e^(ɵ)to2H_(2)O`
In alkaline medium: `H_(2)O_(2)+2e^(ɵ)to2overset(Theta)(O)H`
Hydrogen peroxide acts as a reducing agent towards powerful oxidising agents.
In acidic medium: `H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ)` In alkaline medium, however, its reducing nature is more effective.
`H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ)`
In the reaction, `H_2O_2 + O_3 to H_2O + 2O_2, H_2O_2` behaves as

A

an oxdising agent

B

reducing agent

C

acid

D

base

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The correct Answer is:
To determine the behavior of hydrogen peroxide (H₂O₂) in the reaction with ozone (O₃) to form water (H₂O) and oxygen (O₂), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reaction is: \[ \text{H}_2\text{O}_2 + \text{O}_3 \rightarrow \text{H}_2\text{O} + 2\text{O}_2 \] - Here, the reactants are hydrogen peroxide (H₂O₂) and ozone (O₃), while the products are water (H₂O) and oxygen (O₂). 2. **Determine the Oxidation States**: - In H₂O₂, the oxidation state of oxygen is -1. - In H₂O, the oxidation state of oxygen is -2. - In O₃, the oxidation state of oxygen is 0 (since it is in its elemental form). - In O₂, the oxidation state of oxygen is 0. 3. **Analyze the Changes in Oxidation States**: - For H₂O₂: - The oxidation state of oxygen changes from -1 in H₂O₂ to -2 in H₂O. - This indicates that the oxidation state of oxygen in H₂O₂ is decreasing, which means H₂O₂ is losing electrons. - For O₃: - The ozone (O₃) is being reduced to O₂, indicating that it is gaining electrons. 4. **Determine the Role of H₂O₂**: - Since H₂O₂ is losing electrons (decreasing its oxidation state), it is acting as a reducing agent. - In contrast, ozone (O₃), being a strong oxidizing agent, is gaining electrons. 5. **Conclusion**: - Therefore, in the reaction between H₂O₂ and O₃, hydrogen peroxide behaves as a reducing agent. ### Final Answer: Hydrogen peroxide (H₂O₂) behaves as a **reducing agent** in the reaction with ozone (O₃).

To determine the behavior of hydrogen peroxide (H₂O₂) in the reaction with ozone (O₃) to form water (H₂O) and oxygen (O₂), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reaction is: \[ \text{H}_2\text{O}_2 + \text{O}_3 \rightarrow \text{H}_2\text{O} + 2\text{O}_2 ...
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Hydrogen peroxide is a powerful oxidising agent, both in the acidic and alkaline medium. In acidic medium: H_(2)O_(2)+2H^(o+)+2e^(ɵ)to2H_(2)O In alkaline medium: H_(2)O_(2)+2e^(ɵ)to2overset(Theta)(O)H Hydrogen peroxide acts as a reducing agent towards powerful oxidising agents. In acidic medium: H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ) In alkaline medium, however, its reducing nature is more effective. H_(2)O_(2)to2H^(o+)+O_(2)+2e^(ɵ) H_2O_2 behaves as a bleaching agent due to

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