The compound which gives `H_2O_2` on treatment with dilute acid is

Options

A. `PbO_(2)`
B. `MnO_(2)`
C. `TiO_(2)`
D. `KO_(2)`

Explanation

To determine which compound gives hydrogen peroxide (H₂O₂) when treated with dilute acid, we will analyze each of the given compounds one by one. We will use dilute sulfuric acid (H₂SO₄) for our reactions.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds provided are PbO₂, MnO₂, TiO₂, and KO₂. We need to check which of these reacts with dilute H₂SO₄ to produce H₂O₂.

2. **React PbO₂ with Dilute H₂SO₄**:
- Reaction: PbO₂ + H₂SO₄ → PbSO₄ + H₂O + O₂
- Result: This reaction produces lead sulfate (PbSO₄), water (H₂O), and oxygen (O₂), but **not** H₂O₂.
- Conclusion: PbO₂ does not give H₂O₂.

3. **React MnO₂ with Dilute H₂SO₄**:
- Reaction: MnO₂ + H₂SO₄ → MnSO₄ + H₂O + O₂
- Result: This reaction produces manganese sulfate (MnSO₄), water (H₂O), and oxygen (O₂), but **not** H₂O₂.
- Conclusion: MnO₂ does not give H₂O₂.

4. **React TiO₂ with Dilute H₂SO₄**:
- Reaction: TiO₂ + H₂SO₄ → Ti(SO₄)₂ + H₂O
- Result: This reaction produces titanium sulfate (Ti(SO₄)₂) and water (H₂O), but **not** H₂O₂.
- Conclusion: TiO₂ does not give H₂O₂.

5. **React KO₂ with Dilute H₂SO₄**:
- Reaction: 4 KO₂ + 2 H₂SO₄ → 2 K₂SO₄ + 2 H₂O + O₂ + H₂O₂
- Result: This reaction produces potassium sulfate (K₂SO₄), water (H₂O), oxygen (O₂), and **H₂O₂**.
- Conclusion: KO₂ does give H₂O₂.

6. **Final Answer**: The compound that gives H₂O₂ on treatment with dilute acid is **KO₂**.