One part of heavy water is present in `X` parts of ordinary water. Here `X` is

Options

A. `10`
B. `60`
C. `6000`
D. `60000`

Answer

To solve the question "One part of heavy water is present in `X` parts of ordinary water," we need to understand the relationship between heavy water (D₂O) and ordinary water (H₂O).

### Step-by-Step Solution:

1. **Understanding Heavy Water and Ordinary Water**:
- Heavy water is chemically represented as D₂O, where D stands for deuterium, an isotope of hydrogen.
- Ordinary water is represented as H₂O.

2. **Proportion of Heavy Water in Ordinary Water**:
- It is known that in ordinary water, there is a very small amount of heavy water present. Specifically, it is estimated that there is 1 part of heavy water for every 6000 parts of ordinary water.

3. **Setting Up the Equation**:
- According to the information, if we have 1 part of heavy water (D₂O), it is present in `X` parts of ordinary water (H₂O).
- From the known ratio, we can conclude that:
\[ 1 \text{ part of D₂O} \text{ is present in } 6000 \text{ parts of H₂O} \]
- Therefore, we can say that:
\[ X = 6000 \]

4. **Conclusion**:
- Thus, the value of `X` is 6000. This means that for every 1 part of heavy water, there are 6000 parts of ordinary water.

### Final Answer:
The value of `X` is **6000**.

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