The volume strength of `0.92 N H_2O_2` solution is

Options

A. `4.8`
B. `5.2`
C. `8.8`
D. `8.4`

Explanation

To find the volume strength of a 0.92 N (Normal) H₂O₂ (hydrogen peroxide) solution, we can use the formula that relates volume strength to normality. The formula is:

**Volume Strength = 5.6 × Normality**

### Step-by-Step Solution:

1. **Identify the Normality**:
The problem states that the normality of the H₂O₂ solution is 0.92 N.

2. **Use the Formula**:
We will use the formula for volume strength:
\[ \text{Volume Strength} = 5.6 \times \text{Normality} \]

3. **Substitute the Normality Value**:
Now we substitute the given normality into the formula:
\[ \text{Volume Strength} = 5.6 \times 0.92 \]

4. **Perform the Calculation**:
Now, we perform the multiplication:
\[ 5.6 \times 0.92 = 5.152 \]

5. **Round the Result**:
The calculated volume strength is approximately 5.152. We can round this to one decimal place:
\[ \text{Volume Strength} \approx 5.2 \]

6. **Conclusion**:
Therefore, the volume strength of the 0.92 N H₂O₂ solution is approximately 5.2.

### Final Answer:
The volume strength of 0.92 N H₂O₂ solution is approximately **5.2**.