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Lithium on being heated in air mainly fo...

Lithium on being heated in air mainly forms the monoxide and not peroxide

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To determine whether the statement "Lithium on being heated in air mainly forms the monoxide and not peroxide" is true or false, we can analyze the behavior of lithium when it reacts with oxygen. ### Step-by-Step Solution: 1. **Understanding Lithium's Reaction with Oxygen**: - When lithium is heated in air, it reacts with oxygen. The products of this reaction can include lithium oxide (Li2O) and lithium peroxide (Li2O2). 2. **Formation of Lithium Oxide**: ...
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Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. In hydrolysis, the alkali metals oxides, peroxide and superoxide act as:

Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O_(2)^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. Which anion is stable towards water:

Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O_(2)^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. Which compounds will liberate oxygen when reacts with ice cold water?

Lithium only forms monoxide when heated in oxygen. Sodium forms monoxide and peroxide in excess of oxygen. Other alkali metals form superoxide metals superoxide with oxygen i.e., MO_(2) . The abnormal behaviour of lithium is due to small size. The larger size of higher metals also decides the role in formation of superoxide. All the three anions abstract proton from water. The three anions are raleted to each other as follows: underset("oxide ion")(O_(2)^(2-)overset((1)/(2)O_(2))(to)underset("peroxide ion")(O_(2)^(2-))overset(O_(2))(to)underset("superoxide ion")(2O_(2)^(-)) Q. Consider the following reaction : M+O_(2) to MO_(2) (M=alkali metal) (stable superoxide)

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