In the manufacture of sodium carbonate, following reactions are involved:
`(A) overset(Delta)rarr (B) + CO_(2)`
`(B) +H_(2)O rarr (C ) overset(+NH_(4)Cl rarr (D)overset(+H_(2)O)rarr underset("Solution")(E )`
`(E )+CO_(2)rarr (F)`
`(F)+NaCl rarr (G) overset("Heat")rarr Na_(2)CO_(3)+CO_(2)+H_(2)O`
(D) is a gas which is soluble in `H_(2)O`
(E ) and (F) are

Options

A. `NH_(4)OH` and `NH_(4)HCO_(3)`
B. `NaOH` and `NaHCO_(3)`
C. `Ca(OH)_(2)` and `Ca(HCO_(3))_(2)`
D. None of these

Explanation

To solve the problem regarding the manufacture of sodium carbonate and identify the compounds E and F in the given reactions, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Starting Material (A)**:
The process begins with calcium carbonate (CaCO₃), which is our starting material (A).

2. **Reaction of A**:
When calcium carbonate (A) is heated, it decomposes to form calcium oxide (CaO) and carbon dioxide (CO₂):
\[ \text{CaCO}_3 \overset{\Delta}{\rightarrow} \text{CaO (B)} + \text{CO}_2 \]

3. **Reaction of B with Water**:
Calcium oxide (B) then reacts with water (H₂O) to form calcium hydroxide (C):
\[ \text{CaO (B)} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 (C) \]

4. **Reaction of C with Ammonium Chloride**:
Calcium hydroxide (C) reacts with ammonium chloride (NH₄Cl) to produce ammonia (NH₃), which is a gas (D):
\[ \text{Ca(OH)}_2 (C) + \text{NH}_4\text{Cl} \rightarrow \text{NH}_3 (D) + \text{CaCl}_2 + \text{H}_2\text{O} \]

5. **Dissolution of D in Water**:
The ammonia gas (D) dissolves in water to form ammonium hydroxide (E):
\[ \text{NH}_3 (D) + \text{H}_2\text{O} \rightarrow \text{NH}_4\text{OH} (E) \]

6. **Reaction of E with Carbon Dioxide**:
Ammonium hydroxide (E) reacts with carbon dioxide (CO₂) to form ammonium bicarbonate (F):
\[ \text{NH}_4\text{OH} (E) + \text{CO}_2 \rightarrow \text{NH}_4\text{HCO}_3 (F) \]

7. **Reaction of F with Sodium Chloride**:
Ammonium bicarbonate (F) reacts with sodium chloride (NaCl) to produce sodium bicarbonate (NaHCO₃) and ammonium chloride (NH₄Cl):
\[ \text{NH}_4\text{HCO}_3 (F) + \text{NaCl} \rightarrow \text{NaHCO}_3 (G) + \text{NH}_4\text{Cl} \]

8. **Formation of Sodium Carbonate**:
Sodium bicarbonate (G) is then heated to produce sodium carbonate (Na₂CO₃), carbon dioxide, and water:
\[ 2 \text{NaHCO}_3 (G) \overset{\Delta}{\rightarrow} \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \]

### Conclusion:
From the above reactions, we can conclude that:
- **E** is ammonium hydroxide (NH₄OH).
- **F** is ammonium bicarbonate (NH₄HCO₃).