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In the manufacture of sodium carbonate, ...

In the manufacture of sodium carbonate, following reactions are involved:
`(A) overset(Delta)rarr (B) + CO_(2)`
`(B) +H_(2)O rarr (C ) overset(+NH_(4)Cl rarr (D)overset(+H_(2)O)rarr underset("Solution")(E )`
`(E )+CO_(2)rarr (F)`
`(F)+NaCl rarr (G) overset("Heat")rarr Na_(2)CO_(3)+CO_(2)+H_(2)O`
(D) is a gas which is soluble in `H_(2)O`
(G) is `NaHCO_(3)`. The other compound formed with (G) is

A

`NH_(4)Cl`

B

`NH_(4)OH`

C

`CaCl_(2)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the manufacture of sodium carbonate and the identification of the other compound formed with (G), we will follow the steps outlined in the reactions provided. ### Step-by-Step Solution: 1. **Identify the Starting Material (A)**: The process begins with calcium carbonate (CaCO3), which is heated to produce calcium oxide (CaO) and carbon dioxide (CO2). \[ \text{CaCO}_3 \overset{\Delta}{\rightarrow} \text{CaO} + \text{CO}_2 \quad (A \rightarrow B) \] 2. **Formation of Calcium Hydroxide (C)**: Calcium oxide (B) reacts with water (H2O) to form calcium hydroxide (C). \[ \text{CaO} + \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 \quad (B + H_2O \rightarrow C) \] 3. **Reaction with Ammonium Chloride (D)**: Calcium hydroxide (C) reacts with ammonium chloride (NH4Cl) to produce ammonia (NH3) gas (D) and calcium chloride (CaCl2) along with water. \[ \text{Ca(OH)}_2 + \text{NH}_4\text{Cl} \rightarrow \text{NH}_3 \text{(gas)} + \text{CaCl}_2 + \text{H}_2\text{O} \quad (C + NH_4Cl \rightarrow D) \] 4. **Dissolution of Ammonia (E)**: The ammonia gas (D) dissolves in water to form ammonium hydroxide (E). \[ \text{NH}_3 + \text{H}_2\text{O} \rightarrow \text{NH}_4\text{OH} \quad (D + H_2O \rightarrow E) \] 5. **Formation of Ammonium Bicarbonate (F)**: Ammonium hydroxide (E) reacts with carbon dioxide (CO2) to form ammonium bicarbonate (F). \[ \text{NH}_4\text{OH} + \text{CO}_2 \rightarrow \text{NH}_4\text{HCO}_3 \quad (E + CO_2 \rightarrow F) \] 6. **Formation of Sodium Bicarbonate (G)**: Ammonium bicarbonate (F) reacts with sodium chloride (NaCl) to produce sodium bicarbonate (G) and ammonium chloride (NH4Cl). \[ \text{NH}_4\text{HCO}_3 + \text{NaCl} \rightarrow \text{NaHCO}_3 + \text{NH}_4\text{Cl} \quad (F + NaCl \rightarrow G) \] 7. **Heating of Sodium Bicarbonate**: Sodium bicarbonate (G) is then heated to produce sodium carbonate (Na2CO3), carbon dioxide (CO2), and water (H2O). \[ \text{NaHCO}_3 \overset{\Delta}{\rightarrow} \text{Na}_2\text{CO}_3 + \text{CO}_2 + \text{H}_2\text{O} \quad (G \rightarrow Na2CO3) \] ### Conclusion: The other compound formed with (G) when sodium bicarbonate (NaHCO3) is produced is ammonium chloride (NH4Cl).

To solve the question regarding the manufacture of sodium carbonate and the identification of the other compound formed with (G), we will follow the steps outlined in the reactions provided. ### Step-by-Step Solution: 1. **Identify the Starting Material (A)**: The process begins with calcium carbonate (CaCO3), which is heated to produce calcium oxide (CaO) and carbon dioxide (CO2). \[ \text{CaCO}_3 \overset{\Delta}{\rightarrow} \text{CaO} + \text{CO}_2 \quad (A \rightarrow B) ...
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