The compounds(s) formed upon combustion of sodium metal excess air is/are

Options

A. `Na_(2)O_(2)`
B. `Na_(2)O`
C. `NaO_(2)`
D. NaOH

Explanation

To solve the question regarding the compounds formed upon the combustion of sodium metal in excess air, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**: When sodium (Na) is burned in air, it reacts with oxygen (O2) to form sodium oxides. The combustion of sodium is a reaction with oxygen, which is an essential aspect to consider.

2. **Identifying the Products**:
- In normal conditions, sodium reacts with oxygen to form sodium oxide (Na2O). The balanced equation for this reaction is:
\[ 4 \text{Na} + \text{O}_2 \rightarrow 2 \text{Na}_2\text{O} \]
- However, when there is excess oxygen, sodium can further react to form sodium peroxide (Na2O2). The reaction can be represented as:
\[ 2 \text{Na} + \text{O}_2 \rightarrow \text{Na}_2\text{O}_2 \]

3. **Considering Excess Oxygen**: Since the question specifies "excess air," we can conclude that both sodium oxide (Na2O) and sodium peroxide (Na2O2) can be formed. Sodium superoxide (NaO2) is not formed in this scenario due to size compatibility issues between sodium ions and the larger oxide ions.

4. **Final Products**: Therefore, the compounds formed upon the combustion of sodium metal in excess air are:
- Sodium oxide (Na2O)
- Sodium peroxide (Na2O2)

### Conclusion:
The correct answer to the question is that the compounds formed are sodium oxide (Na2O) and sodium peroxide (Na2O2).