Which of the following compound(s) will impart a golden yellow
colour to the Bunsen flame ?

Options

A. `KCl`
B. `K_(2)CO_(3)`
C. `NaCl`
D. `Na_(2)CO_(3)`

Explanation

To determine which of the following compounds will impart a golden yellow color to the Bunsen flame, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compounds**: Start by listing the compounds in question. In this case, we are considering compounds of alkali metals, particularly sodium and potassium.

2. **Understand Flame Test**: The flame test is a qualitative analysis technique used to identify the presence of certain metal ions based on the color they emit when heated in a flame.

3. **Know the Characteristic Colors**: Each alkali metal has a characteristic flame color:
- **Lithium**: Crimson red
- **Sodium**: Golden yellow
- **Potassium**: Pale violet
- **Rubidium**: Red violet
- **Cesium**: Blue

4. **Focus on Sodium Compounds**: Since we are looking for the golden yellow color, we need to focus on sodium compounds. The compounds of sodium that are commonly tested include:
- Sodium chloride (NaCl)
- Sodium carbonate (Na2CO3)

5. **Determine the Flame Color**: When sodium compounds (like NaCl and Na2CO3) are heated in a Bunsen flame, they will impart a golden yellow color due to the excitation of electrons in sodium ions.

6. **Conclusion**: Therefore, the compounds that will impart a golden yellow color to the Bunsen flame are:
- **NaCl (Sodium Chloride)**
- **Na2CO3 (Sodium Carbonate)**

### Final Answer:
The compounds that will impart a golden yellow color to the Bunsen flame are NaCl and Na2CO3.

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