`Na_(2)CO_(3)+Fe_(2)O_(3)rarr A+CO_(2)`, what is A in the reaction ?

Options

A. `NaFeO_(2)`
B. `Na_(3)FeO_(3)`
C. `Fe_(3)O_(4)`
D. `Na_(2)FeO_(2)`

Explanation

To determine the compound A in the reaction \( \text{Na}_2\text{CO}_3 + \text{Fe}_2\text{O}_3 \rightarrow A + \text{CO}_2 \), we can follow these steps:

### Step 1: Write the Balanced Equation
We start with the given reaction:
\[ \text{Na}_2\text{CO}_3 + \text{Fe}_2\text{O}_3 \rightarrow A + \text{CO}_2 \]

### Step 2: Identify the Elements and Their Counts
On the reactant side, we have:
- Sodium (Na): 2
- Carbon (C): 1
- Oxygen (O): 3 (from Na2CO3) + 3 (from Fe2O3) = 6
- Iron (Fe): 2

On the product side, we have:
- Carbon (C): 1 (from CO2)
- Oxygen (O): 2 (from CO2)

### Step 3: Calculate Remaining Atoms
Now, we will calculate the remaining atoms after accounting for CO2 on the product side:
- Sodium (Na): 2 (remains)
- Iron (Fe): 2 (remains)
- Oxygen (O): 6 (total from reactants) - 2 (from CO2) = 4 remaining

### Step 4: Determine the Formula for A
To balance the remaining atoms, we need to combine the remaining sodium, iron, and oxygen. Since we have:
- 2 Sodium (Na)
- 2 Iron (Fe)
- 4 Oxygen (O)

We can combine these to form:
\[ \text{Na}_2\text{Fe}_2\text{O}_4 \]
However, this can be simplified to:
\[ \text{NaFeO}_2 \]
This indicates that we have 2 moles of sodium ferrite (NaFeO2).

### Step 5: Finalize the Compound A
Thus, the compound A in the reaction is:
\[ A = \text{NaFeO}_2 \]

### Conclusion
The final answer is:
\[ \text{A} = \text{NaFeO}_2 \]

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