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Tin dissolves in excess of sodium hydrox...

Tin dissolves in excess of sodium hydroxide solution to form _____________ .

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To solve the question "Tin dissolves in excess of sodium hydroxide solution to form _____________", we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants in this reaction are tin (Sn) and sodium hydroxide (NaOH). 2. **Understand the Reaction**: ...
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A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue R is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Name the salt formed when S dissolves in excess of sodium hydroxide.

A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue R is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Identify the solid P.

A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue R is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Name the coloured gas R.

A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue R is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Name the residue Q.

A white solid P, on strong heating, decomposes to give reddish brown gas R and a residue Q. The residue Q is yellow when hot and white when cold. The solution of white solid P in water gives white precipitate S, with concentrated sodium hydroxide. The white precipitate S dissolves in excess of sodium hydroxide solution to form colourless solution. Another sample of the solid P in water is mixed with ferrous sulphate solution and then to this solution are added a few drops of conc. sulphuric acid. A brown ring is formed at the junction of liquids. Answer the following questions: Name the white precipitate S.

A black solid P dissolves in warm and dilute HCI to form greenish yellow solution Q, but does not give off any gas. The solution Q on treating with ammonium hydroxide forms bluish white precipitates of R. The precipitates of R dissolve in excess of ammonium hydroxide. solution to form deep-blue colouration. Identify solid P and bluish white precipitates of R. Write equations for action of excess of ammonium hydroxide on R.

Salts P, Q,R,S,T,U and V undergo reactions (i) to (vii) respectively. Identify the cation present in these salts on the basis of these reactions. Tabulate your answer in the formate given below. (i) When the salt Pis heated with sodium hydroxide solution a vigorous reaction takes place and a colourless gas is evolved with a pungent and suffocating smell that brings tears in our eyes. The evolved gas gives dense white fumes with a moist glass rod depped with hydrochloric acid. (ii) Addition of sodium hydroxide solution to a solution of salt Q gives a thick white precipitae which is soluble in excess of sodium hydroxide solution to form a clear solution. (iii) Addition of ammonium hydroxide solution to a solution of salt R gives a dark blue precipitate which is soluble is excess of ammonium hydroxide solution to form an intense deep blue solution. (iv) Addition of ammonium hydroxide solution to a solution of 5 gives a dirty green [bottle green] precipitate which is insoluble even in the excess of ammonium hydroxide solution. (v) Addition of ammonium hydroxide solution to a solution of T gives a reddish brown (rust precipitate] precipitate which is insoluble even in the excess of ammonium hydroxide solution. (vi) Addition of ammonium hydroxide solution to a solution of V gives a geletaneous white precipitate which is soluble in excess of ammonium hydroxide solution to form a clear solution. (vii) Addition of ammonium hydroxide solution to a solution of V gives no precipitate but it gives a chalky white precipitate with sodium hydroxide solution which is insoluble even in the excess of sodium hydroxide solution.

A black solid P dissolves in warm and dilute HCI to form greenish blue solution Q, but does not give off any gas. The solution Q on treating with ammonium hydroxide forms bluish white precipitates of R. The precipitates of R dissolve in excess of ammonium hydroxide. solution to form deep-blue colouration. Identify solid P and bluish white precipitates of R. Write equations for Action of less amount of ammonium hydroxide on Q.

When Al is added to sodium hydroxide solution:

When sodium hydroxide solution is electrolysed :