Sodium nitrate decomposes above-`800^(@)C` to give

Options

A. `N_(2)`
B. `O_(2)`
C. `NO_(2)`
D. `Na_(2)O`

Explanation

To solve the question regarding the decomposition of sodium nitrate above `800°C`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Decomposition Reaction**:
Sodium nitrate (NaNO₃) decomposes when heated. The general reaction for the decomposition of sodium nitrate can be represented as:
\[ 2 \text{NaNO}_3 \rightarrow \text{Na}_2\text{O} + \text{N}_2 + \frac{5}{2} \text{O}_2 \]

2. **Understand the Products**:
From the balanced equation, we can see that the products of the decomposition are:
- Sodium oxide (Na₂O)
- Nitrogen gas (N₂)
- Oxygen gas (O₂)

3. **Analyze the Temperature Condition**:
The question specifies that the decomposition occurs above `800°C`. This temperature is significant because it indicates that the reaction will proceed to form the products listed above.

4. **List the Options**:
The options provided in the question likely include:
- A) N₂
- B) O₂
- C) NO₂
- D) Na₂O

5. **Determine the Correct Answers**:
Based on the decomposition reaction:
- N₂ is produced (Correct)
- O₂ is produced (Correct)
- NO₂ is not produced (Incorrect)
- Na₂O is produced (Correct)

6. **Final Conclusion**:
Therefore, the correct products of the decomposition of sodium nitrate above `800°C` are:
- N₂
- O₂
- Na₂O

### Final Answer:
The correct products formed from the decomposition of sodium nitrate above `800°C` are N₂, O₂, and Na₂O.