`Al_(2)(SO_(4))_(3) + NH_(4)OH rarr X , X` is.

Options

A. A white gelatinous precipitate
B. Soluble in excess of `NH_(4)OH`
C. Soluble in excess of `NaOH`
D. Amphoteric in nature.

Explanation

To solve the question regarding the reaction of aluminum sulfate \( \text{Al}_2(\text{SO}_4)_3 \) with ammonium hydroxide \( \text{NH}_4\text{OH} \), we can follow these steps:

### Step 1: Write the Reactants
The reactants in the reaction are:
- Aluminum sulfate: \( \text{Al}_2(\text{SO}_4)_3 \)
- Ammonium hydroxide: \( \text{NH}_4\text{OH} \)

### Step 2: Determine the Products
When aluminum sulfate reacts with ammonium hydroxide, it produces:
- Aluminum hydroxide: \( \text{Al(OH)}_3 \)
- Ammonium sulfate: \( \text{(NH}_4)_2\text{SO}_4 \)

### Step 3: Write the Balanced Chemical Equation
The balanced equation for the reaction can be written as:
\[ \text{Al}_2(\text{SO}_4)_3 + 6 \text{NH}_4\text{OH} \rightarrow 2 \text{Al(OH)}_3 + 3 \text{(NH}_4)_2\text{SO}_4 \]

### Step 4: Identify the Characteristics of the Product \( X \)
The product \( X \) here is aluminum hydroxide \( \text{Al(OH)}_3 \). This compound has the following characteristics:
- It forms a white gelatinous precipitate when produced in the reaction.
- It is amphoteric in nature, meaning it can react with both acids and bases.
- It is insoluble in water but soluble in excess sodium hydroxide, forming sodium tetrahydroxoaluminate.

### Step 5: Conclusion
Thus, the product \( X \) formed in the reaction is aluminum hydroxide \( \text{Al(OH)}_3 \).

### Summary of the Solution
The final answer is:
\[ X = \text{Al(OH)}_3 \text{ (aluminum hydroxide)} \]