In which of the following, a salt of the type `KMO_(2)` is obtained ?

Options

A. `B_(2)H_(6) + KOH_((aq)) rarr`
B. `Al + KOH_((aq)) rarr`
C. Both
D. None

Explanation

To determine in which of the following reactions a salt of the type \( KMO_2 \) is obtained, we will analyze the reactions step by step.

### Step 1: Identify the Reactions
We are given two reactions:
1. \( B_2H_6 + KOH \) (aqueous)
2. \( Al + KOH \) (aqueous)

### Step 2: Complete the First Reaction
For the first reaction:
- When diborane (\( B_2H_6 \)) reacts with aqueous potassium hydroxide (\( KOH \)), the products formed are potassium borate (\( KBO_2 \)) and hydrogen gas (\( H_2 \)).
- The balanced equation is:
\[ B_2H_6 + 6 KOH \rightarrow 2 KBO_2 + 6 H_2 \]

### Step 3: Identify the Type of Salt
- The salt \( KBO_2 \) is of the type \( KMO_2 \), where \( M \) is boron (B).

### Step 4: Complete the Second Reaction
For the second reaction:
- When aluminum (\( Al \)) reacts with aqueous potassium hydroxide (\( KOH \)), the products formed are potassium aluminate (\( K_3AlO_3 \)) and hydrogen gas (\( H_2 \)).
- The balanced equation is:
\[ 2 Al + 2 KOH + 6 H_2O \rightarrow 2 K_3AlO_3 + 3 H_2 \]

### Step 5: Identify the Type of Salt
- The salt \( K_3AlO_3 \) is of the type \( K_3MO_3 \), where \( M \) is aluminum (Al).

### Conclusion
From the analysis:
- The first reaction produces a salt of the type \( KMO_2 \) (specifically \( KBO_2 \)).
- The second reaction produces a salt of the type \( K_3MO_3 \) (specifically \( K_3AlO_3 \)).

Thus, the correct option that yields a salt of the type \( KMO_2 \) is the first reaction.

### Final Answer
The correct answer is **Option A**.

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