Home
Class 11
CHEMISTRY
Which excess of NaOH solution is added i...

Which excess of `NaOH` solution is added in potash alum the product is.

A

A bluish precipitate

B

Clear solution

C

White precipitate

D

Greenish precipitate

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of what product is formed when excess NaOH solution is added to potash alum, we can follow these steps: ### Step 1: Identify the Composition of Potash Alum Potash alum is a double sulfate of potassium and aluminum, with the chemical formula: \[ \text{K}_2\text{SO}_4 \cdot \text{Al}_2(\text{SO}_4)_3 \cdot 24\text{H}_2\text{O} \] ### Step 2: Understand the Reaction with NaOH When potash alum is treated with excess sodium hydroxide (NaOH), the aluminum sulfate component reacts with NaOH. The aluminum sulfate can be represented as: \[ \text{Al}_2(\text{SO}_4)_3 \] ### Step 3: Write the Reaction The reaction between aluminum sulfate and sodium hydroxide can be represented as follows: \[ \text{Al}_2(\text{SO}_4)_3 + 6\text{NaOH} \rightarrow 2\text{NaAlO}_2 + 3\text{Na}_2\text{SO}_4 + 6\text{H}_2\text{O} \] ### Step 4: Identify the Products From the reaction, we can see that the products formed are: 1. Sodium aluminate (\( \text{NaAlO}_2 \)), which is soluble in water. 2. Sodium sulfate (\( \text{Na}_2\text{SO}_4 \)), which is also soluble in water. 3. Water (\( \text{H}_2\text{O} \)). ### Step 5: Conclusion Since both sodium aluminate and sodium sulfate are soluble, the overall result of adding excess NaOH to potash alum is a clear solution containing these soluble products. ### Final Answer The product formed when excess NaOH solution is added to potash alum is a clear solution containing sodium aluminate and sodium sulfate. ---
To solve the question of what product is formed when excess NaOH solution is added to potash alum, we can follow these steps: ### Step 1: Identify the Composition of Potash Alum Potash alum is a double sulfate of potassium and aluminum, with the chemical formula: \[ \text{K}_2\text{SO}_4 \cdot \text{Al}_2(\text{SO}_4)_3 \cdot 24\text{H}_2\text{O} \] ### Step 2: Understand the Reaction with NaOH When potash alum is treated with excess sodium hydroxide (NaOH), the aluminum sulfate component reacts with NaOH. The aluminum sulfate can be represented as: ...
Promotional Banner

Topper's Solved these Questions

  • P-BLOCK GROUP 13 - BORON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercise (Assertion-Reasoning)|13 Videos

  • P-BLOCK GROUP 13 - BORON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercise (Integer)|9 Videos

  • P-BLOCK GROUP 13 - BORON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercise (Multiple Correct)|23 Videos

  • ORGANIC REACTION MECHANISM

    CENGAGE CHEMISTRY ENGLISH|Exercise Analytical and Descriptive|6 Videos

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Subjective)|9 Videos

Similar Questions

Explore conceptually related problems

State any one observation for each of the NaOH solution is added to calcium nitrate solution.

When Al is added to NaOH solution

FeC_3 is added separately to excess of boiling water and excess of NaOH solution, the sols obtained contain respectively the disperse particles to be :

Identify the cations in each of the following cases: i] NaOH solution when added to the solution 'A' - gives a reddish brown precipitate. ii] NH_4OH solution when added to the solution 'B' - gives a white ppt which does not dissolve in excess. jii] NaOH solution when added to the solution 'C' - gives a white ppt which is insoluble in excess.

When excess sodium thiosulphate is added to AgBr, the product formed is

Aqueous solution of potash alum is:

A colourless solid A dissolves in water. The aqueous solution gives a white precipitate B when NaOH or NH_4 OH is added. B dissolves in excess of NaOH but not in excess of NH_4OH . BaCl2 solution added to a solution of A gives a white precipitate C which is insoluble in dilute HCI. A may be

State your observations in each of the following: Ammonium hydroxide solution is added slowly in excess to the product obtained on treating heated iron with chlorine.

A mixture of ferric alum, chrome alum and potash alum is dissolved in water and treated with an excess of NH_(3) solution annd warmed with a mixture of NaOH and H_(2)O_(2) and filtered. We will get:

When a solution of sodium hydroxide is addeed in excess to the solution of potash alum, we obtain