Boron nitride is isoelectronic with

Options

A. `C_(2)`
B. `B_(2)`
C. `N_(2)`
D. `O_(2)`

Explanation

To determine which species is isoelectronic with boron nitride (BN), we need to follow these steps:

### Step 1: Understand Isoelectronic Species
Isoelectronic species are atoms, ions, or molecules that have the same number of electrons. Therefore, to find an isoelectronic species for boron nitride, we first need to calculate the total number of electrons in BN.

### Step 2: Calculate the Total Number of Electrons in Boron Nitride (BN)
- Boron (B) has 5 electrons.
- Nitrogen (N) has 7 electrons.
- Therefore, the total number of electrons in boron nitride (BN) is:
\[ \text{Total electrons in BN} = \text{Electrons in B} + \text{Electrons in N} = 5 + 7 = 12 \]

### Step 3: Identify Possible Isoelectronic Species
Now that we know BN has 12 electrons, we need to check which of the given options also has 12 electrons.

1. **C2 (Diatomic Carbon)**:
- Each carbon atom has 6 electrons.
- Therefore, for C2:
\[ \text{Total electrons in C2} = 2 \times 6 = 12 \]

2. **B2 (Diatomic Boron)**:
- Each boron atom has 5 electrons.
- Therefore, for B2:
\[ \text{Total electrons in B2} = 2 \times 5 = 10 \]

3. **N2 (Diatomic Nitrogen)**:
- Each nitrogen atom has 7 electrons.
- Therefore, for N2:
\[ \text{Total electrons in N2} = 2 \times 7 = 14 \]

4. **O2 (Diatomic Oxygen)**:
- Each oxygen atom has 8 electrons.
- Therefore, for O2:
\[ \text{Total electrons in O2} = 2 \times 8 = 16 \]

### Step 4: Conclusion
From the calculations:
- C2 has 12 electrons (isoelectronic with BN).
- B2 has 10 electrons.
- N2 has 14 electrons.
- O2 has 16 electrons.

Thus, the only species that is isoelectronic with boron nitride (BN) is **C2**.

### Final Answer
Boron nitride (BN) is isoelectronic with **C2**.

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