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In solid state PCl(5) exist as [PCl(4)]^...

In solid state `PCl_(5)` exist as `[PCl_(4)]^(+) [PCl_(6)]^(-)`. The hybridisation of P is /are

A

`sp^3 d^2`

B

`sp^3 d`

C

`sp^3`

D

`sp^2`

Text Solution

Verified by Experts

The correct Answer is:
C
Solid `PCl_5` is `[PCl_4)^(oplus) [PCl_6]^(Ө)`
`[PCl_4]^(oplus) = "Tetrahedral", [PCl_6]^(Ө) = "Octahedral"`.
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