On hydrolysis of magnesium nitride, how many moles of ammonia are produced ?

Explanation

To determine how many moles of ammonia are produced from the hydrolysis of magnesium nitride, we can follow these steps:

### Step 1: Write the unbalanced chemical equation
The first step is to write the unbalanced chemical equation for the hydrolysis of magnesium nitride (Mg₃N₂) with water (H₂O).

**Equation:**
\[ \text{Mg}_3\text{N}_2 + \text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 + \text{NH}_3 \]

### Step 2: Identify the products
From the hydrolysis of magnesium nitride, we know that the products are magnesium hydroxide (Mg(OH)₂) and ammonia (NH₃).

### Step 3: Balance the chemical equation
Next, we need to balance the equation. Start by counting the number of each type of atom on both sides of the equation.

1. **Nitrogen (N):** There are 2 nitrogen atoms in Mg₃N₂, so we need 2 NH₃ on the product side.
2. **Magnesium (Mg):** There are 3 magnesium atoms in Mg₃N₂, so we need 3 Mg(OH)₂ on the product side.
3. **Hydrogen (H) and Oxygen (O):** After balancing Mg and N, we will check the hydrogen and oxygen atoms.

The balanced equation will look like this:
\[ \text{Mg}_3\text{N}_2 + 6 \text{H}_2\text{O} \rightarrow 3 \text{Mg(OH)}_2 + 2 \text{NH}_3 \]

### Step 4: Determine the moles of ammonia produced
From the balanced equation, we can see that 1 mole of magnesium nitride (Mg₃N₂) produces 2 moles of ammonia (NH₃).

### Conclusion
Thus, the answer to the question is that **2 moles of ammonia are produced** on the hydrolysis of 1 mole of magnesium nitride.

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