Which of the following will displace the halogen form the solution of the halide ?

Options

A. `Br_(2)` added to NaCI solution
B. `CI_(2)` added to KCI solution
C. `CI_(2)` added to NaF solution
D. `Br_(2)` added to KI solution

Answer

To determine which of the following will displace the halogen from the solution of the halide, we need to understand the concept of oxidizing power among halogens. The halogens have varying oxidizing strengths, which dictate whether one halogen can displace another from its compound.

### Step-by-Step Solution:

1. **Understand the Oxidizing Power of Halogens**:
- The oxidizing power of halogens decreases in the order:
\[ \text{F}_2 > \text{Cl}_2 > \text{Br}_2 > \text{I}_2 \]
- This means that fluorine is the strongest oxidizing agent, followed by chlorine, bromine, and iodine.

2. **Evaluate Each Option**:
- **Option A: Br2 + NaCl**:
- Here, bromine (Br2) is trying to displace chlorine (Cl) from sodium chloride (NaCl).
- Since Cl2 has a higher oxidizing power than Br2, bromine cannot displace chlorine.
- **Conclusion**: No displacement occurs.

- **Option B: Cl2 + KCl**:
- Chlorine (Cl2) is trying to displace chlorine from potassium chloride (KCl).
- Since they are the same halogen, Cl2 cannot displace Cl from KCl.
- **Conclusion**: No displacement occurs.

- **Option C: Cl2 + NaF**:
- Chlorine (Cl2) is trying to displace fluorine (F) from sodium fluoride (NaF).
- Since fluorine has a higher oxidizing power than chlorine, Cl2 cannot displace F.
- **Conclusion**: No displacement occurs.

- **Option D: Br2 + KI**:
- Bromine (Br2) is trying to displace iodine (I) from potassium iodide (KI).
- Since bromine has a higher oxidizing power than iodine, Br2 can displace I.
- The reaction will produce iodine (I2) and potassium bromide (KBr).
- **Conclusion**: Displacement occurs.

3. **Final Answer**:
- The correct option is **D: Br2 + KI** as bromine can displace iodine from potassium iodide.