Which of the following is soluble in water ?

Options

A. AgF
B. AgBr
C. AgCI
D. AgI

Explanation

To determine which of the following compounds is soluble in water: AgF, AgBr, AgCl, or AgI, we can analyze each compound based on their properties and interactions with water.

### Step-by-Step Solution:

1. **Understanding Solubility in Water**:
- Solubility in water often depends on the polarity of the compound. Polar substances tend to dissolve well in polar solvents like water.

2. **Analyzing Each Compound**:
- **AgF (Silver Fluoride)**:
- Fluorine is highly electronegative, which means it creates a very polar bond with silver. The high polarity leads to a significant ionic character, making it more soluble in water. Additionally, fluorine can form hydrogen bonds with water, enhancing its solubility.

- **AgBr (Silver Bromide)**:
- Bromine is less electronegative than fluorine. The bond between silver and bromine is less polar compared to AgF, resulting in lower ionic character. Therefore, AgBr is less soluble in water.

- **AgCl (Silver Chloride)**:
- Chlorine is also less electronegative than fluorine. Similar to AgBr, the bond between silver and chlorine is not very polar, leading to low solubility in water.

- **AgI (Silver Iodide)**:
- Iodine is the least electronegative among the halogens mentioned. The bond with silver is even less polar, resulting in minimal ionic character and very low solubility in water.

3. **Conclusion**:
- Among the compounds listed, only **AgF (Silver Fluoride)** is soluble in water due to its high polarity and ability to form hydrogen bonds.

### Final Answer:
**AgF (Silver Fluoride) is soluble in water.**