When chlorine water is added to an aqueous solution of sodium iodide in the presence of chloroform, a violet colouration is obtained. On adding more of chlorine water and vigorous shakinh, the violet colour disappear. This shows the conversion of …….. into .......

Options

A. `I_(2),HIO_(3)`
B. `I_(2),HI`
C. `HI,HiO_(3)`
D. `I_(2),HOI`

Explanation

To solve the question, we need to analyze the chemical reactions occurring when chlorine water is added to an aqueous solution of sodium iodide in the presence of chloroform.

### Step-by-Step Solution:

1. **Understanding the Initial Reaction**:
When chlorine water (which contains Cl2) is added to an aqueous solution of sodium iodide (NaI), a reaction occurs where chlorine displaces iodine from sodium iodide. The reaction can be represented as:
\[ \text{Cl}_2 + 2 \text{NaI} \rightarrow 2 \text{NaCl} + \text{I}_2 \]
Here, iodine (I2) is produced, which imparts a violet color when dissolved in chloroform (CCl4).

2. **Observing the Violet Color**:
The violet coloration observed is due to the presence of iodine (I2) in the chloroform layer. Iodine is known to form a colored solution in organic solvents like chloroform.

3. **Adding More Chlorine Water**:
When more chlorine water is added and the mixture is shaken vigorously, the violet color disappears. This indicates that the iodine (I2) is being further reacted.

4. **Identifying the Reaction**:
The additional chlorine reacts with the iodine to form iodic acid (HIO3) and hydrochloric acid (HCl). The overall reaction can be represented as:
\[ \text{Cl}_2 + 6 \text{H}_2\text{O} + \text{I}_2 \rightarrow 2 \text{HIO}_3 + 10 \text{HCl} \]
This reaction consumes the iodine, leading to the disappearance of the violet color.

5. **Conclusion**:
From the above reactions, we can conclude that the conversion is from iodine (I2) into iodic acid (HIO3).

### Final Answer:
The conversion is from **I2 into HIO3**.

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