For `(A)+K_(2)CO_(3)+"air" overset(Heat)rarr(B)`
`(B)+Cl_(2)rarr(C)`pink
Which of the following is correct ?

Options

A. (A) is black, `MnO_(2)`, (B) is blue, `K_(2)MnO_(4)` and (C) is pink, `KMnO_(4)`
B. (A) is green, `Cr_(2)O_(3)`, (B) is yellow, `K_(2)CrO_(4)` and (C ) is pink, `K_(2)Cr_(2)O_(7)`
C. (A) is black, `MnO_(2)`, (B) is green, `K_(2)MnO_(4)` and (C ) is pink, `KMnO_(4)`
D. (A) is black, `Bi_(2)O_(3)`, (B) is colourless, `KBiO_(2)` and (C ) is pink, `KMnO_(3)`

Explanation

To solve the problem step by step, we will analyze the reactions and identify the compounds involved:

### Step 1: Identify Compound A
- The reaction starts with compound A, which is reacted with K2CO3 and air (oxygen) upon heating.
- From the video transcript, it is mentioned that compound A is manganese dioxide (MnO2), which is a black-colored compound.

**Hint for Step 1:** Look for the reactants and their typical reactions to identify the starting compound.

### Step 2: Determine Compound B
- When MnO2 is heated with K2CO3 and air, it produces compound B.
- The product formed is potassium manganate (K2MnO4), which is green in color.

**Hint for Step 2:** Consider the type of reactions that occur when metal oxides react with carbonates in the presence of oxygen.

### Step 3: Identify Compound C
- Compound B (K2MnO4) then reacts with chlorine (Cl2) to form compound C.
- The reaction of potassium manganate with chlorine produces potassium permanganate (KMnO4), which is pink in color.

**Hint for Step 3:** Look for the oxidation reactions involving chlorine and manganese compounds to determine the final product.

### Step 4: Summarize the Compounds
- **Compound A:** MnO2 (black)
- **Compound B:** K2MnO4 (green)
- **Compound C:** KMnO4 (pink)

### Conclusion
The correct option based on the analysis is:
- A is a black-colored compound (MnO2), B is a green-colored compound (K2MnO4), and C is a pink-colored compound (KMnO4).

**Final Answer:** The correct option is that A is black-colored (MnO2), B is green-colored (K2MnO4), and C is pink-colored (KMnO4).

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