`HCIO_(4)+P_(2)O_(5)rarr(A)+(B)`
(A) and (B) are

Options

A. `HCIO_(3),H_(3)PO_(4)`
B. `CI_(2)O_(6),HPO_(3)`
C. `CIO_(2)H_(3)PO_(4)`
D. `CI_(2)O_(7),HPO_(3)`

Explanation

To solve the question regarding the reaction between HClO₄ and P₂O₅, we need to identify the products A and B formed from this reaction. Here’s a step-by-step breakdown of the solution:

### Step 1: Write the Reactants
The reactants given in the question are:
- HClO₄ (Perchloric acid)
- P₂O₅ (Phosphorus pentoxide)

### Step 2: Identify the Reaction
When HClO₄ reacts with P₂O₅, it typically leads to the formation of two products. The reaction can be represented as:
\[ \text{HClO}_4 + \text{P}_2\text{O}_5 \rightarrow (A) + (B) \]

### Step 3: Determine the Products
From the knowledge of chemical reactions involving HClO₄ and P₂O₅, we can deduce that the products formed are:
- A = Cl₂O₇ (Dichlorine heptoxide)
- B = HPO₃ (Phosphorous acid)

### Step 4: Write the Balanced Equation
The balanced chemical equation for the reaction can be written as:
\[ 2 \text{HClO}_4 + \text{P}_2\text{O}_5 \rightarrow \text{Cl}_2\text{O}_7 + 2 \text{HPO}_3 \]

### Step 5: Conclusion
Thus, the two compounds A and B formed from the reaction of HClO₄ and P₂O₅ are:
- A = Cl₂O₇
- B = HPO₃

### Final Answer
(A) = Cl₂O₇, (B) = HPO₃

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