The noble gases have closed-shell electronic configuration and are monatomic gases under normal condition .The low bolling points of the ligher noble gases aree due to the weak dispersion points of the ligher noble gases an due to the weak dispersion forces between the atoms and the alsence of other interalumic interactions.
The direct reaction of xenon with flarine loads to a series of compounds with water oxidation number `+2, - 4 and +6, XeF_(4)` reactsviolenatly with water to give `XeO_(2)` .The compound of deduced axbibt nci strouchemistry and their goometries can be deduced considering the total number of electron puirs in the valence shell.
The structure of `XeO_(3)` is

Options

A. linear
B. planar
C. pyramidal
D. T-shaped

Answer

To determine the structure of the compound XeO3, we will follow these steps:

### Step 1: Identify the Central Atom
In XeO3, xenon (Xe) is the central atom.

### Step 2: Determine the Valence Electrons
Xenon is a noble gas and has 8 valence electrons. Oxygen (O) has 6 valence electrons, but since we have three oxygen atoms, we will focus on how they bond with xenon.

### Step 3: Use the Hybridization Formula
We will use the hybridization formula:
\[ H = \frac{1}{2} (V + M - C) \]
Where:
- \( V \) = number of valence electrons of the central atom (Xe = 8)
- \( M \) = number of monovalent atoms (0 in this case, as O is divalent)
- \( C \) = charge on the molecule (0 for neutral molecules)

### Step 4: Calculate Hybridization
Substituting the values into the formula:
\[ H = \frac{1}{2} (8 + 0 - 0) = \frac{1}{2} (8) = 4 \]
This means there are 4 hybrid orbitals, indicating that the hybridization is \( sp^3 \).

### Step 5: Determine the Geometry
For \( sp^3 \) hybridization, the geometry is tetrahedral. However, we need to account for the lone pairs.

### Step 6: Account for Lone Pairs
In XeO3, xenon forms double bonds with three oxygen atoms. Each double bond uses 2 of xenon's valence electrons, totaling 6 electrons used (3 double bonds). This leaves 2 electrons, which form one lone pair on xenon.

### Step 7: Determine the Molecular Shape
While the geometry is tetrahedral, the presence of one lone pair alters the molecular shape. We ignore the lone pair when determining the shape, leading to a pyramidal shape for XeO3.

### Conclusion
The structure of XeO3 is pyramidal.

### Summary of Steps:
1. Identify the central atom (Xe).
2. Determine valence electrons (8 for Xe).
3. Use the hybridization formula to calculate hybridization (sp3).
4. Determine geometry (tetrahedral).
5. Account for lone pairs (1 lone pair).
6. Determine molecular shape (pyramidal).