The complex `M(C_(4)O_(4))CI_(2)(NH_(3))_(2)` forms two types of ionic coloured crystals viz red (A) and blue `(B)` A or `B` reacts with 1 mole of `AgNO_(3)` to give `1//2` mole of a red precipitate Further 1 mole of A reacts slowly with 1 mole of `Ag_(2)C_(2)O_(4)` to form 2 moles of a white precipitate bit `B` does not react with `Ag_(2)C_(2)O_(4)` From the above data Find
(a) the coordination number of `M`
(b) the hybrid orbitals of `M`

Explanation

`1mol e (A) underset(Ag_(2)C_(2)O_(4))overset(1mo1 of)rarr2mol e ofwhite ppt`
`1mol e (B) underset(Ag_(2)C_(2)O_(4))overset(1mo1 of)rarrNo reaction`
(i) Both `(A)` and `(B)` react with 1 mole of `AgNO_(3)` to give `(1)/(2)mo1` of red ppt This shows `C_(2)O_(4)^(2-)` ion is a counter ions

(ii) Coordination number of `M=4`
So, `A` and `B` both have square planner complex `A` is cis and `B` trans

(iii) `B` does not react with `Ag_(2)C_(2)O_(4)` so it is trans isomer Hence
isomer .