The total number of possibel coordination isomer for the given compounds `[Pt(NH_(3))(4)Br_(2)][PtBr_(4)]` is .

Options

A. `2`
B. `4`
C. `5`
D. `3`

Explanation

To determine the total number of possible coordination isomers for the given compounds \([Pt(NH_3)_4Br_2]\) and \([PtBr_4]\), we will follow these steps:

### Step 1: Identify the Coordination Compounds
We have two coordination compounds:
1. \([Pt(NH_3)_4Br_2]\) - This is a complex with 4 ammonia (NH3) ligands and 2 bromine (Br) ligands.
2. \([PtBr_4]\) - This is a complex with 4 bromine (Br) ligands.

### Step 2: Understand Coordination Isomers
Coordination isomers occur when there is an interchange of ligands between the coordination spheres of the metal centers. In this case, we can exchange the ligands between the two complexes.

### Step 3: Determine Possible Isomers
For the complex \([Pt(NH_3)_4Br_2]\), we can have the following coordination isomers by exchanging the ligands:

1. **Isomer 1**: \([Pt(NH_3)_4Br_2]\) - No exchange.
2. **Isomer 2**: \([Pt(NH_3)_3Br_3]\) - One NH3 ligand is replaced by Br.
3. **Isomer 3**: \([Pt(NH_3)_2Br_4]\) - Two NH3 ligands are replaced by Br.
4. **Isomer 4**: \([Pt(NH_3)Br_5]\) - Three NH3 ligands are replaced by Br.

### Step 4: Count the Isomers
From the above analysis, we can see that there are 4 distinct coordination isomers for the complex \([Pt(NH_3)_4Br_2]\).

### Step 5: Conclusion
Thus, the total number of possible coordination isomers for the given compounds is 4.

### Final Answer
The total number of possible coordination isomers for the given compounds \([Pt(NH_3)_4Br_2]\) and \([PtBr_4]\) is **4**.

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