The compounds `[PtBr_(2)(NH_(3))_(2)]` can form .

Options

A. Geometrical isomers
B. Coordination isomers
C. Optical isomers
D. Linkage isomers

Answer

To determine the types of isomers that the compound `[PtBr₂(NH₃)₂]` can form, we will analyze the coordination compound step by step.

### Step 1: Identify the Coordination Compound
The given compound is `[PtBr₂(NH₃)₂]`. Here, platinum (Pt) is the central metal atom, and it is coordinated to two bromide ions (Br⁻) and two ammonia molecules (NH₃).

### Step 2: Determine Possible Isomerism Types
We need to consider the types of isomerism that can occur with this compound:
1. **Geometrical Isomerism**: This occurs when ligands can be arranged differently around the central metal atom.
2. **Coordination Isomerism**: This involves the exchange of ligands between cationic and anionic complexes.
3. **Optical Isomerism**: This occurs when a compound can exist in two non-superimposable mirror images.
4. **Linkage Isomerism**: This occurs when a ligand can coordinate to the metal through different atoms.

### Step 3: Analyze Geometrical Isomerism
In the case of `[PtBr₂(NH₃)₂]`, we can have two arrangements:
- **Cis Isomer**: Both bromide ions are adjacent to each other, and both ammonia ligands are adjacent to each other.
- **Trans Isomer**: The bromide ions are opposite each other, and the ammonia ligands are also opposite each other.

Since the compound has two different types of ligands (Br and NH₃), it can exhibit geometrical isomerism.

### Step 4: Analyze Other Types of Isomerism
- **Coordination Isomerism**: This does not apply here as there is no cationic-anionic complex present.
- **Optical Isomerism**: This compound is not chiral, as it can be superimposed on its mirror image due to the presence of two identical ligands (NH₃).
- **Linkage Isomerism**: This does not apply here as the ligands present (Br and NH₃) do not have multiple donor atoms.

### Conclusion
The compound `[PtBr₂(NH₃)₂]` can form geometrical isomers (cis and trans), but it does not exhibit coordination, optical, or linkage isomerism.

### Final Answer
The compound `[PtBr₂(NH₃)₂]` can form **geometrical isomers**.

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