One mole of complex compound `Cr(NH_(3))_(5)CI_(3)` gives 3 moles of ions on dissolution in water One mole of the same complex reacts with two moles of AgNO3 to yield two moles of AgCl The complex is :

Options

A. a.`[Cr(NH_(3))_(4)Cl]Cl_(2).NH_(3)`
B. b.`[Cr(NH_(3))_(4)Cl_(2)]Cl.NH_(3)`
C. c.`[Cr(NH_(3))_(5)Cl]Cl_(2)`
D. d.`[Cr(NH_(3))Cl_(3).2NH_(3)`

Explanation

To solve the problem step by step, we need to analyze the information provided about the complex compound `Cr(NH3)5Cl3`.

### Step 1: Understand the Dissociation of the Complex
The complex `Cr(NH3)5Cl3` is a coordination compound. When it dissolves in water, it dissociates into ions. According to the question, one mole of this complex gives 3 moles of ions upon dissolution.

### Step 2: Determine the Composition of the Complex
The formula `Cr(NH3)5Cl3` indicates that there is one chromium ion (Cr), five ammonia ligands (NH3), and three chloride ions (Cl). The ammonia ligands do not dissociate into ions, but the chloride ions do.

### Step 3: Analyze the Ion Formation
When `Cr(NH3)5Cl3` dissolves:
- It forms one complex ion: `Cr(NH3)5^3+`
- It releases three chloride ions: `3Cl^-`

Thus, the total number of ions formed is:
1 complex ion + 3 chloride ions = 4 moles of ions.

However, the problem states that it gives 3 moles of ions. This indicates that not all chloride ions are counted as separate ions in the context of the complex.

### Step 4: Reaction with AgNO3
The problem states that one mole of the complex reacts with two moles of AgNO3 to yield two moles of AgCl. This implies that two chloride ions are involved in the reaction with silver nitrate (AgNO3) to form silver chloride (AgCl).

### Step 5: Conclusion on the Composition
Since the complex gives 3 moles of ions and reacts with 2 moles of AgNO3 to yield 2 moles of AgCl, we can conclude that:
- There are 2 chloride ions that are available for reaction with AgNO3.
- The remaining ion must be the complex ion itself.

Thus, the complex must be `Cr(NH3)5Cl2` (with 2 chloride ions) and not `Cr(NH3)5Cl3`.

### Final Answer
The complex is `Cr(NH3)5Cl2`.

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