(A) (colourless solution ) gives white ppt (B) with `NaOH` solution but ppt dissolves in excess of `NaOH` forming (C ). (C ) does not give ppt with `H_(2)S` but on boiling with `NH_(4)CI`, white ppt (B) appears. (A) also gives yellow ppt with `AgNO_(3)` identify (A),(B) and (C )

Explanation

To solve the problem, we need to identify the compounds A, B, and C based on the given reactions and observations. Here's a step-by-step breakdown:

### Step 1: Identify Compound A
- The problem states that a colorless solution (A) gives a white precipitate (B) with NaOH.
- A common colorless solution that forms a white precipitate with NaOH is aluminum bromide (AlBr3).

**Conclusion:** A = Aluminum bromide (AlBr3)

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