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Cations are classified into varius group...

Cations are classified into varius group on the basis of their behaviour against some reagents .The group reagent used for the classifaction of most common cation are `HCI,H_(2)S,NH_(4)OH,(NH_(4))_(2)CO_(3)`. Classification is based on whether a cation reacts with these reagents by the formation of precipitates or not .
Which one among the following paires of ions cannot be separated by `H_(2)S` in the presence of dilute hydrochloric acid ?

A

`Bi^(2+),Cd^(2+)`

B

`AI^(2+),Hg^(2+)`

C

`Zn^(3+),Cu^(2+)`

D

`Ni^(2+),Cu^(2+)`

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To solve the question regarding which pair of ions cannot be separated by H₂S in the presence of dilute hydrochloric acid (HCl), we will follow these steps: ### Step 1: Understand the Classification of Cations Cations are classified into different groups based on their behavior with certain reagents. The reagents mentioned are HCl, H₂S, NH₄OH, and (NH₄)₂CO₃. In this case, we are focusing on the second group of cations, which typically includes ions like Mercuric (Hg²⁺), Lead (Pb²⁺), Bismuth (Bi³⁺), Copper (Cu²⁺), and Cadmium (Cd²⁺). ### Step 2: Identify the Role of H₂S and Dilute HCl H₂S acts as a group reagent for the second group of cations when used in conjunction with dilute HCl. In this environment, certain cations will form insoluble sulfides, which precipitate out of the solution. ### Step 3: Analyze the Precipitation of Cations In the presence of dilute HCl and H₂S: - Bismuth (Bi³⁺) forms a black precipitate of Bismuth sulfide (Bi₂S₃). - Cadmium (Cd²⁺) forms a yellow precipitate of Cadmium sulfide (CdS). Both of these cations will precipitate out as sulfides and thus cannot be separated from each other in this solution. ### Step 4: Conclusion Since both Bismuth and Cadmium form precipitates when treated with H₂S in the presence of dilute HCl, they cannot be separated from each other. Therefore, the answer to the question is the pair of ions that includes Bismuth and Cadmium. ### Final Answer The pair of ions that cannot be separated by H₂S in the presence of dilute hydrochloric acid is **Bismuth (Bi³⁺) and Cadmium (Cd²⁺)**. ---

To solve the question regarding which pair of ions cannot be separated by H₂S in the presence of dilute hydrochloric acid (HCl), we will follow these steps: ### Step 1: Understand the Classification of Cations Cations are classified into different groups based on their behavior with certain reagents. The reagents mentioned are HCl, H₂S, NH₄OH, and (NH₄)₂CO₃. In this case, we are focusing on the second group of cations, which typically includes ions like Mercuric (Hg²⁺), Lead (Pb²⁺), Bismuth (Bi³⁺), Copper (Cu²⁺), and Cadmium (Cd²⁺). ### Step 2: Identify the Role of H₂S and Dilute HCl H₂S acts as a group reagent for the second group of cations when used in conjunction with dilute HCl. In this environment, certain cations will form insoluble sulfides, which precipitate out of the solution. ...
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Cations are classified into varius group on the basis of their behaviour against some reagents .The group reagent used for the classifaction of most common cation are HCI,H_(2)S,NH_(4)OH,(NH_(4))_(2)CO_(3) Classification is based on whether a cation reacts with these reagents by the formation of precipitates or not . An aqueous solution contain Hg^(2+),Hg_(2)^(2+),Pb^(2+) .THe addition of 2M HCI will procipitate.

Cations are classified into varius group on the basis of their behaviour against some reagents .The group reagent used for the classifaction of most common cation are HCI,H_(2)S,NH_(4)OH,(NH_(4))_(2)CO_(3) . Classification is based on whether a cation reacts with these reagents by the formation of precipitates or not . An aqucous solution which is sightly acids contains cattions Fe^(2+),Zn^(2+) and Cu^(2+) . THe rengent added in excess to this solution would identify the separate Fe^(2+) ion in one step is

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Which of the following pairs of cations cannot be separated by adding NH_(4)Cl and NH_(4)OH to the mixture and then passing H_(2)S through it?

Which of the following pairs of cations cannot be separated by adding NH_(4)Cl and NH_(4)OH to the mixture and then passing H_(2)S through it?

CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Exercises (Linked Comprehension)
  1. Find the anion (s)

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  2. Find out (E )

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  3. Find out (F)

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  4. Cations are classified into varius group on the basis of their behav...

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  5. Cations are classified into varius group on the basis of their behav...

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  6. Cations are classified into varius group on the basis of their behav...

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  7. The reagents like AgNO(3),K(4)[Fe(CN)(6)],KCNS,KI,K(2)CrO(4) Nessler's...

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  8. The reagents like AgNO(3),K(4)[fe(CN)(6)],KCNS,KI,K(2)CrO(4) Nessler's...

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  9. The reagents like AgNO(3),K(4)[Fe(CN)(6)],KCNS,KI,K(2)CrO(4) Nessler's...

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  10. NH(3) solution was added to four semple solution in difference test t...

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  11. NH(3) solution was added to four semple solution in difference test t...

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  12. NH(3) solution was added to four semple solution in difference test t...

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  13. (A) is a colourless solid, it metal when heated and gives of a gas (...

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  14. (A) is a colourless solid, it metal when heated and gives of a gas (...

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  15. (A) is a colourless solid, it metal when heated and gives of a gas (...

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  16. Which of the following statement is/are correct for gas (D) ? (I)it h...

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  17. Compound (B) on reaction with [Na(en)(3)][NO(3))(2) gives a coloured ...

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  18. A colourless (A) when place into water a heavy white turbidly of (B) s...

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  19. A colourless (A) when place into water a heavy white turbidly of (B) s...

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  20. A colourless (A) when place into water a heavy white turbidly of (B) s...

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