The reagents like `AgNO_(3),K_(4)[Fe(CN)_(6)],KCNS,KI,K_(2)CrO_(4)` Nessler's ect, find extenstive and very important applicasion in quentitative analysis because these resgents form different type of produce with different cation for axample `KI` form yellow precipitate with `Pb^(2+)` but at form red iprecipitate with `Hg^(2+)` , Hence these reagents are widely used in the quantitative amalysis of morgenic salts
Which of the following hydroxide does not dissolve in ammounium solution but disolves in sodium hydroxide ?

Options

A. `Zn(OH)_(2)`
B. `Cd(OH)_(2)`
C. `Cu(OH)_(2)`
D. `AI(OH)_(3)`

Explanation

To solve the question regarding which hydroxide does not dissolve in ammonium solution but dissolves in sodium hydroxide, we will analyze the behavior of each hydroxide with respect to the two reagents: ammonium hydroxide (NH₄OH) and sodium hydroxide (NaOH).

### Step-by-Step Solution:

1. **Identify the Hydroxides:**
The question provides four hydroxides to analyze: Zinc hydroxide (Zn(OH)₂), Cadmium hydroxide (Cd(OH)₂), Copper hydroxide (Cu(OH)₂), and Aluminum hydroxide (Al(OH)₃).

2. **Analyze Zinc Hydroxide (Zn(OH)₂):**
- When zinc hydroxide is treated with sodium hydroxide (NaOH), it forms a soluble complex:
\[ \text{Zn(OH)}_2 + 2 \text{NaOH} \rightarrow \text{Na}_2[\text{Zn(OH)}_4] \]
- When treated with ammonium hydroxide (NH₄OH), it also forms a soluble complex:
\[ \text{Zn(OH)}_2 + 4 \text{NH}_3 \rightarrow [\text{Zn(NH}_3)_4]^{2+} \]
- **Conclusion:** Zinc hydroxide dissolves in both NaOH and NH₄OH.

3. **Analyze Cadmium Hydroxide (Cd(OH)₂):**
- Cadmium hydroxide does dissolve in ammonium hydroxide:
\[ \text{Cd(OH)}_2 + 2 \text{NH}_3 \rightarrow [\text{Cd(NH}_3)_2]^{2+} \]
- However, it does not dissolve in sodium hydroxide.
- **Conclusion:** Cadmium hydroxide dissolves in NH₄OH but not in NaOH.

4. **Analyze Copper Hydroxide (Cu(OH)₂):**
- Copper hydroxide dissolves in ammonium hydroxide:
\[ \text{Cu(OH)}_2 + 4 \text{NH}_3 \rightarrow [\text{Cu(NH}_3)_4]^{2+} \]
- It does not dissolve in sodium hydroxide.
- **Conclusion:** Copper hydroxide dissolves in NH₄OH but not in NaOH.

5. **Analyze Aluminum Hydroxide (Al(OH)₃):**
- Aluminum hydroxide does not dissolve in ammonium hydroxide:
\[ \text{Al(OH)}_3 + \text{NH}_4\text{OH} \rightarrow \text{No reaction} \]
- However, it does dissolve in sodium hydroxide:
\[ \text{Al(OH)}_3 + \text{NaOH} \rightarrow \text{Na}_2[\text{Al(OH)}_4] \]
- **Conclusion:** Aluminum hydroxide does not dissolve in NH₄OH but dissolves in NaOH.

6. **Final Answer:**
Based on the analysis, the hydroxide that does not dissolve in ammonium solution but dissolves in sodium hydroxide is **Aluminum hydroxide (Al(OH)₃)**.