`I_(2)` can be obtained from `KI` solution by the action of

Options

A. `CI_(2)`
B. `Br_(2)`
C. Soluble `CI^(Θ)`
D. Solution `Br^(Θ)`

Answer

To obtain iodine (I₂) from potassium iodide (KI) solution, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reactivity of Halogens**:
The halogens have varying reactivities, which can be arranged in the following order: Fluorine (F₂) > Chlorine (Cl₂) > Bromine (Br₂) > Iodine (I₂). This order indicates that fluorine is the strongest oxidizing agent, followed by chlorine and bromine.

2. **Identifying the Oxidizing Agents**:
Chlorine (Cl₂) and bromine (Br₂) are capable of oxidizing iodide ions (I⁻) to form iodine (I₂). This means that these halogens can displace iodine from potassium iodide.

3. **Writing the Reaction with Chlorine**:
When chlorine gas is bubbled through a potassium iodide solution, it reacts as follows:
\[ 2KI + Cl_2 \rightarrow 2KCl + I_2 \]
In this reaction, chlorine oxidizes iodide ions to iodine.

4. **Writing the Reaction with Bromine**:
Similarly, when bromine is introduced to potassium iodide, the following reaction occurs:
\[ 2KI + Br_2 \rightarrow 2KBr + I_2 \]
Here, bromine also oxidizes iodide ions to form iodine.

5. **Conclusion**:
Therefore, iodine (I₂) can be obtained from potassium iodide (KI) solution by the action of chlorine (Cl₂) or bromine (Br₂).

### Final Answer:
Iodine (I₂) can be obtained from potassium iodide (KI) solution by the action of chlorine (Cl₂) or bromine (Br₂).

---