Aqueous solution contains `Zn(CH_(2)COO)_(2),Cd(CH_(3)COO)_(2) and Cu(CH_(3)COO)_(2)` on passing `H_(2)S` gas, therte is a precipitate of ……. As sulphide

Options

A. `Zn^(2+)`
B. `Cd^(2+)`
C. `Cu^(2+)`
D. None of these

Answer

To solve the problem, we need to analyze the behavior of the given metal acetates when hydrogen sulfide (H₂S) gas is passed through their aqueous solutions. The metal acetates provided are zinc acetate (Zn(CH₂COO)₂), cadmium acetate (Cd(CH₃COO)₂), and copper acetate (Cu(CH₃COO)₂).

### Step-by-Step Solution:

1. **Identify the Cations**:
- The compounds dissociate in solution to give their respective cations:
- Zinc acetate → Zn²⁺
- Cadmium acetate → Cd²⁺
- Copper acetate → Cu²⁺

2. **Understanding the Reaction with H₂S**:
- When H₂S gas is bubbled through the solution, it reacts with the metal cations to form metal sulfides:
- Zn²⁺ + H₂S → ZnS (s)
- Cd²⁺ + H₂S → CdS (s)
- Cu²⁺ + H₂S → CuS (s)

3. **Formation of Precipitates**:
- All three metal sulfides (ZnS, CdS, and CuS) are insoluble in water and will precipitate out of the solution upon the addition of H₂S.

4. **Conclusion**:
- Therefore, the precipitate formed when H₂S is passed through the solution containing zinc acetate, cadmium acetate, and copper acetate will be a mixture of ZnS, CdS, and CuS.

### Final Answer:
The precipitate formed as sulfide is **ZnS, CdS, and CuS**.

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