Which of the following will be completely or parially dissolved in `NH_(4)OH` ?

Options

A. `AgCI`
B. `AgBr`
C. `BaSO_(4)`
D. `AgI`

Explanation

To determine which compounds are completely or partially dissolved in ammonium hydroxide (NH₄OH), we need to analyze the solubility of each compound in the presence of NH₄OH. The compounds given are AgCl, AgBr, AgI, and BaSO₄.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds we need to analyze are:
- AgCl (Silver Chloride)
- AgBr (Silver Bromide)
- AgI (Silver Iodide)
- BaSO₄ (Barium Sulfate)

2. **Understand Ammonium Hydroxide**: Ammonium hydroxide (NH₄OH) is a source of NH₃ (ammonia) in aqueous solution. It can form complexes with certain metal ions.

3. **Analyze AgCl**:
- AgCl is known to be soluble in NH₄OH. When AgCl is treated with NH₄OH, it forms a soluble complex:
\[ \text{AgCl} + 2\text{NH}_3 \rightarrow \text{Ag(NH}_3\text{)}_2\text{Cl} + \text{H}_2\text{O} \]
- **Conclusion**: AgCl is completely soluble in NH₄OH.

4. **Analyze AgBr**:
- AgBr is less soluble than AgCl but can still dissolve partially in NH₄OH, forming a complex:
\[ \text{AgBr} + 2\text{NH}_3 \rightarrow \text{Ag(NH}_3\text{)}_2\text{Br} + \text{H}_2\text{O} \]
- **Conclusion**: AgBr is partially soluble in NH₄OH.

5. **Analyze AgI**:
- AgI is known to be insoluble in NH₄OH and does not form a complex. Therefore, it remains undissolved.
- **Conclusion**: AgI is insoluble in NH₄OH.

6. **Analyze BaSO₄**:
- BaSO₄ is also insoluble in NH₄OH and does not form any complex with it.
- **Conclusion**: BaSO₄ is insoluble in NH₄OH.

### Final Answer:
The compounds that will be completely or partially dissolved in NH₄OH are:
- **AgCl** (completely soluble)
- **AgBr** (partially soluble)

### Summary:
- **AgCl**: Completely soluble in NH₄OH.
- **AgBr**: Partially soluble in NH₄OH.
- **AgI**: Insoluble in NH₄OH.
- **BaSO₄**: Insoluble in NH₄OH.