A white precipitate insoluble in conc `HNO_(3)` is formed when aqueous solution of X in `NaOH` is treated with barium chloride and bromine water .The X is

Options

A. `SO_(3)`
B. `SO_(2)`
C. `CO_(2)`
D. None of these

Explanation

To solve the problem, we need to identify the compound X that forms a white precipitate when treated with barium chloride and bromine water in the presence of sodium hydroxide. The precipitate is also insoluble in concentrated nitric acid (HNO3). Let's break down the steps:

### Step-by-Step Solution:

1. **Identify the Reaction Conditions**:
- We have a solution of X in NaOH.
- This solution is treated with barium chloride (BaCl2) and bromine water (Br2 in H2O).

2. **Determine the Nature of X**:
- The problem states that a white precipitate is formed. This suggests that X must be a compound that can react to form a barium salt, which is typically a sulfate or sulfite, as barium sulfate (BaSO4) is known to be a white precipitate.

3. **Consider Possible Compounds**:
- The options include various sulfur compounds. Since we are looking for a compound that forms a precipitate with barium chloride, we can consider sulfur dioxide (SO2) as a candidate.

4. **Reactions Involved**:
- When sulfur dioxide (SO2) is dissolved in sodium hydroxide (NaOH), it forms sodium sulfite (Na2SO3):
\[ SO2 + 2NaOH \rightarrow Na2SO3 + H2O \]
- Next, sodium sulfite (Na2SO3) reacts with barium chloride (BaCl2) to form barium sulfite (BaSO3), which is a white precipitate:
\[ Na2SO3 + BaCl2 \rightarrow BaSO3 (s) + 2NaCl \]

5. **Role of Bromine Water**:
- The bromine water (Br2 in H2O) can oxidize the sulfite to sulfate:
\[ 2Na2SO3 + Br2 + 2H2O \rightarrow 2Na2SO4 + 2HBr \]
- The barium sulfate (BaSO4) formed from the oxidation is also a white precipitate and is insoluble in concentrated HNO3:
\[ BaSO3 + O \rightarrow BaSO4 (s) \]

6. **Conclusion**:
- Since the compound X that leads to the formation of a white precipitate (BaSO4) which is insoluble in concentrated HNO3 is sulfur dioxide (SO2), we conclude that:
- The compound X is **sulfur dioxide (SO2)**.

### Final Answer:
The compound X is **sulfur dioxide (SO2)**.