`CaCO_(3)(s) + CH_(3)COOH underset(Na_(2)C_(2)O_(4) "solution") to` ?
Comment on the product of this reaction

Options

A. No reaction
B. White ppt of `(CH_(3)COO)_(2) Ca` is obtained
C. White ppt of `CaC_(2)O_(4)` is formed
D. No ppt is obtained

Explanation

To solve the question regarding the reaction of calcium carbonate (CaCO₃) with acetic acid (CH₃COOH) in the presence of sodium oxalate (Na₂C₂O₄), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are calcium carbonate (CaCO₃), acetic acid (CH₃COOH), and sodium oxalate (Na₂C₂O₄).

2. **Reaction of Calcium Carbonate with Acetic Acid**:
- When calcium carbonate reacts with acetic acid, it produces calcium ions (Ca²⁺), carbon dioxide (CO₂), and water (H₂O).
- The balanced chemical equation for this reaction is:
\[ CaCO₃(s) + 2 CH₃COOH(aq) \rightarrow Ca(CH₃COO)₂(aq) + CO₂(g) + H₂O(l) \]

3. **Formation of Calcium Acetate**:
- The product of this reaction includes calcium acetate (Ca(CH₃COO)₂), which is soluble in water.

4. **Addition of Sodium Oxalate**:
- When sodium oxalate is added to the solution containing calcium ions, a precipitation reaction occurs.
- Calcium ions react with oxalate ions (C₂O₄²⁻) to form calcium oxalate (CaC₂O₄), which is a white precipitate.
- The balanced equation for this reaction is:
\[ Ca^{2+}(aq) + Na₂C₂O₄(aq) \rightarrow CaC₂O₄(s) + 2 Na^+(aq) \]

5. **Observation of the Precipitate**:
- The calcium oxalate precipitate is white and does not dissolve in acetic acid, indicating that it is stable under these conditions.

6. **Conclusion**:
- The final product of the overall reaction is a white precipitate of calcium oxalate (CaC₂O₄).

### Comment on the Product:
The product of the reaction is calcium oxalate, which appears as a white precipitate. This precipitate does not dissolve in acetic acid, indicating its stability in the presence of this acid.