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Aqueous solution of a salt (Y) is alkali...

Aqueous solution of a salt (Y) is alkaline to litmus. On strong heating it swells-up to give a glassy material .When conc `H_(2)SO_(4)` in added to a hot concentrated solution of (Y) white crystals of a weak acid separate out .Hence , the compound (Y) is

A

`Na_(2)SO_(4).10H_(2)O`

B

`Ca_(2)P_(4)O_(11).10H_(2)O`

C

`Na_(2)B_(6)O_(11)`

D

`Na_(2)B_(4)O_(7).10H_(2)O`

Text Solution

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The correct Answer is:
To determine the compound (Y) based on the given properties, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Properties of Compound (Y)**: - The solution of (Y) is alkaline to litmus. - Upon strong heating, it swells and forms a glassy material. - When concentrated sulfuric acid (H₂SO₄) is added to a hot concentrated solution of (Y), white crystals of a weak acid separate out. 2. **Determine the Nature of the Alkaline Solution**: - An alkaline solution indicates the presence of a strong base. Common salts that yield alkaline solutions include borax (sodium tetraborate, Na₂B₄O₇·10H₂O), which dissociates in water to form sodium hydroxide (NaOH). 3. **Heating of Compound (Y)**: - When borax is heated, it swells and forms a glassy material known as sodium metaborate (NaBO₂) and boric anhydride (B₂O₃). The reaction can be represented as: \[ \text{Na}_2\text{B}_4\text{O}_7 \cdot 10\text{H}_2\text{O} \xrightarrow{\text{heat}} 2\text{NaBO}_2 + \text{B}_2\text{O}_3 + 10\text{H}_2\text{O} \] 4. **Reaction with Concentrated Sulfuric Acid**: - When borax reacts with concentrated sulfuric acid, it produces boric acid (H₃BO₃) and sodium sulfate (Na₂SO₄): \[ \text{Na}_2\text{B}_4\text{O}_7 + \text{H}_2\text{SO}_4 + \text{H}_2\text{O} \rightarrow 4\text{H}_3\text{BO}_3 + \text{Na}_2\text{SO}_4 \] - The formation of white crystals indicates the production of boric acid, which is a weak acid. 5. **Conclusion**: - Based on the properties and reactions described, the compound (Y) is identified as borax, which is chemically represented as Na₂B₄O₇·10H₂O. ### Final Answer: The compound (Y) is **sodium tetraborate (borax), Na₂B₄O₇·10H₂O**. ---
To determine the compound (Y) based on the given properties, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Properties of Compound (Y)**: - The solution of (Y) is alkaline to litmus. - Upon strong heating, it swells and forms a glassy material. - When concentrated sulfuric acid (H₂SO₄) is added to a hot concentrated solution of (Y), white crystals of a weak acid separate out. ...
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