An orange red precipitate obtained by passing `H_(2)S` through an acidified solution of an inorganic salt indicates the presence of

Options

A. Cadmium
B. Tin
C. Antimony
D. Bismuth

Explanation

To determine the presence of an orange-red precipitate when hydrogen sulfide (H₂S) is passed through an acidified solution of an inorganic salt, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**: When H₂S is passed through an acidified solution, it can react with various metal ions present in the solution to form metal sulfides. The color of the precipitate formed can help identify the specific metal ion.

2. **Identifying the Metal Ions**: The key to solving this question is to know which metal ions produce an orange-red precipitate when reacting with H₂S. The most common metal that produces such a precipitate is **mercury (II) ions (Hg²⁺)**.

3. **Formation of Precipitate**: When H₂S is introduced into an acidified solution containing mercury (II) ions, it reacts to form mercury (II) sulfide (HgS), which appears as an orange-red precipitate.

4. **Conclusion**: Therefore, the presence of an orange-red precipitate upon passing H₂S through an acidified solution indicates the presence of **mercury (II) ions (Hg²⁺)** in the solution.

### Final Answer:
The orange-red precipitate obtained by passing H₂S through an acidified solution of an inorganic salt indicates the presence of **mercury (II) ions (Hg²⁺)**.

---