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A black sulphide is formed by the action...

A black sulphide is formed by the action of `H_(2)S` on

A

`CaCI_(2)`

B

`CdCI_(2)`

C

`ZnCI_(2)`

D

`NaCI`

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The correct Answer is:
To determine which salt forms a black sulfide when treated with hydrogen sulfide (H₂S), we will analyze the given options: calcium chloride, cadmium chloride, zinc chloride, and sodium chloride. ### Step-by-Step Solution: 1. **Identify the salts**: The salts given are: - Calcium chloride (CaCl₂) - Cadmium chloride (CdCl₂) - Zinc chloride (ZnCl₂) - Sodium chloride (NaCl) 2. **Understand the action of H₂S**: Hydrogen sulfide (H₂S) can react with certain metal ions to form metal sulfides. Some of these sulfides are colored, and we are specifically looking for a black sulfide. 3. **Analyze each salt**: - **Calcium chloride (CaCl₂)**: When H₂S reacts with calcium ions, it forms calcium sulfide (CaS), which is typically white and not black. - **Cadmium chloride (CdCl₂)**: When H₂S reacts with cadmium ions, it forms cadmium sulfide (CdS), which is yellow in color. - **Zinc chloride (ZnCl₂)**: When H₂S reacts with zinc ions, it forms zinc sulfide (ZnS), which is white and not black. - **Sodium chloride (NaCl)**: Sodium does not form a sulfide with H₂S that is colored; it remains soluble. 4. **Identify the black sulfide**: The black sulfide we are looking for is copper sulfide (CuS). However, copper chloride (CuCl₂) is not listed among the options. 5. **Conclusion**: Based on the analysis, none of the provided options will yield a black sulfide with H₂S. The black sulfide is typically associated with copper compounds, specifically copper chloride (CuCl₂), which is not included in the options. ### Final Answer: None of the given options (calcium chloride, cadmium chloride, zinc chloride, sodium chloride) form a black sulfide when reacted with H₂S. The black sulfide is formed by copper chloride, which is not listed.

To determine which salt forms a black sulfide when treated with hydrogen sulfide (H₂S), we will analyze the given options: calcium chloride, cadmium chloride, zinc chloride, and sodium chloride. ### Step-by-Step Solution: 1. **Identify the salts**: The salts given are: - Calcium chloride (CaCl₂) - Cadmium chloride (CdCl₂) - Zinc chloride (ZnCl₂) ...
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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Exercises (Single Correct) Part-C (Analysis Of Cations)
  1. Lead has been placed in qualitative group analysis 1st and 2nd because

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  2. As(2)S(3) is

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  3. A black sulphide is formed by the action of H(2)S on

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  4. The group II precipitate soluble in yellow ammonium sulphide may be

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  5. Dolute nitric acid is generally not used for the preparation of origin...

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  6. The sulphide not soluble in hot dilute nitric acid is

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  7. H(2)S will precipitate the sulphide of all the metals from the soluti...

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  8. To a solution of a substance gradual addition of ammonium hydroxide ...

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  9. A compound is soluble in water. If ammonia is added to aqueous solutio...

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  10. A light green coloured salt soluble in water gives black percipitate o...

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  11. All ammonium salts liberate ammonia when :

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  12. Manganese salt + PbO(2) + conc. HNO(2) rarr The solution has purple ...

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  13. An orange precipitate of group II is dissolve in conc HCI the solutio...

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  14. Which of the following solution gives precipitate with Pb(NO(3))(2) bu...

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  15. A white powder when strongly heated gives off brown fumes. A solutio...

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  16. The ion that cannot be precipitate by both HCI and H(2)S is

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  17. The presence of magnesium is confimed in the qualitative analysis by t...

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  18. In qualitative inorganic analysis phosphate , if present, is to be eli...

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  19. Na(2)CO(3) cannot be used in place of (NH(4))(2)CO(3) for the precipit...

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  20. Disodium hydrogen phosphate is used to test :

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