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To a solution of a substance gradual ad...

To a solution of a substance gradual addition of ammonium hydroxide result in a black precipitate which does not dissolve in excess of `NH_(4)OH` however when HCI is added to the original solution a white precipitate is formed .The solution containe

A

Lead salt

B

Silver salt

C

Mercurous salt

D

Copper salt

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The correct Answer is:
To solve the question, we need to analyze the behavior of the given solution when ammonium hydroxide (NH4OH) and hydrochloric acid (HCl) are added. The observations made during the experiment will help us identify the cation present in the solution. ### Step-by-Step Solution: 1. **Identify the Reaction with Ammonium Hydroxide:** - When ammonium hydroxide is added gradually to the solution, a black precipitate is formed. This indicates that the cation present in the solution could potentially be from a salt that produces a black precipitate upon reaction with NH4OH. 2. **Evaluate Possible Cations:** - **Lead (Pb²⁺):** When Pb²⁺ reacts with NH4OH, it forms a white precipitate of lead hydroxide (Pb(OH)₂). This is not consistent with the observation of a black precipitate. - **Silver (Ag⁺):** The reaction of Ag⁺ with NH4OH produces a brown precipitate of silver oxide (Ag₂O). This also does not match the observation of a black precipitate. - **Mercurous (Hg₂²⁺):** The reaction of mercurous ions with NH4OH produces a black precipitate, specifically a mixture of mercury(I) oxide (HgO) and other compounds. This matches the observation of a black precipitate that does not dissolve in excess NH4OH. - **Copper (Cu²⁺):** The reaction of Cu²⁺ with NH4OH leads to the formation of a blue precipitate of copper hydroxide (Cu(OH)₂), which does not match the observation. 3. **Identify the Reaction with Hydrochloric Acid:** - When HCl is added to the original solution, a white precipitate is formed. This indicates that the cation must also react with HCl to form a white precipitate. - For mercurous salts, the reaction with HCl can lead to the formation of mercurous chloride (Hg₂Cl₂), which is a white precipitate. 4. **Conclusion:** - Based on the observations, the only cation that fits both criteria (formation of a black precipitate with NH4OH and a white precipitate with HCl) is **mercurous salt (Hg₂²⁺)**. ### Final Answer: The solution contains **mercurous salt (Hg₂²⁺)**. ---

To solve the question, we need to analyze the behavior of the given solution when ammonium hydroxide (NH4OH) and hydrochloric acid (HCl) are added. The observations made during the experiment will help us identify the cation present in the solution. ### Step-by-Step Solution: 1. **Identify the Reaction with Ammonium Hydroxide:** - When ammonium hydroxide is added gradually to the solution, a black precipitate is formed. This indicates that the cation present in the solution could potentially be from a salt that produces a black precipitate upon reaction with NH4OH. 2. **Evaluate Possible Cations:** ...
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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Exercises (Single Correct) Part-C (Analysis Of Cations)
  1. The sulphide not soluble in hot dilute nitric acid is

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  2. H(2)S will precipitate the sulphide of all the metals from the soluti...

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  3. To a solution of a substance gradual addition of ammonium hydroxide ...

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  4. A compound is soluble in water. If ammonia is added to aqueous solutio...

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  5. A light green coloured salt soluble in water gives black percipitate o...

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  6. All ammonium salts liberate ammonia when :

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  7. Manganese salt + PbO(2) + conc. HNO(2) rarr The solution has purple ...

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  8. An orange precipitate of group II is dissolve in conc HCI the solutio...

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  9. Which of the following solution gives precipitate with Pb(NO(3))(2) bu...

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  10. A white powder when strongly heated gives off brown fumes. A solutio...

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  11. The ion that cannot be precipitate by both HCI and H(2)S is

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  12. The presence of magnesium is confimed in the qualitative analysis by t...

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  13. In qualitative inorganic analysis phosphate , if present, is to be eli...

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  14. Na(2)CO(3) cannot be used in place of (NH(4))(2)CO(3) for the precipit...

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  15. Disodium hydrogen phosphate is used to test :

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  16. Reddish - brown (chocolate ) ppt. is formed with :

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  17. Addition of SnCl(2) to HgCl(2) gives precipitate:

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  18. To avoid the precipitation of hydroxides of Ni^(2+),Co^(2+),Zn^(2+) an...

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  19. Which of the gives a white precipitate with a solution of AgNO(3), a ...

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  20. In qualitative inorganic analysis of basic radicals hydrochloric acid ...

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